从字符串中删除特殊字符以通过jQuery过滤数据

Question

I have a string like this:

var str = "f2025%20%3D%20%2209%3A00%22%20and%20f5118288%20%3D%20%222017-03-31%22#";

How can I remove all special characters {'%20%3D%20%22','%3A','%22%20','%20'} from the above string to return list value like this {'f2025', '09', '00', 'and', 'f5118288', '2017-03-31'}

Answer 1

You can use the following regex to split the string

%20%3D%20%22|%3A|%22%20|%20|%22#

using this split function

var str = "f2025%20%3D%20%2209%3A00%22%20and%20f5118288%20%3D%20%222017-03-31%22#";
var strArray = str.split(/%20%3D%20%22|%3A|%22%20|%20|%22#/)

Answer 2

You can use replace with special character and split for desire result.

 var str = "f2025%20%3D%20%2209%3A00%22%20and%20f5118288%20%3D%20%222017-03-31%22#"; str = str.replace(/%20%3D%20%22/g, "@").replace(/%3D/g, "").replace(/%3A/g, "@").replace(/%22%20/g, "@").replace(/#/g, "").replace(/%20/g, "@").replace(/%22/g, "@"); var Result = str.split('@'); alert(Result); 

 <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>