简体   繁体   English

如何在Entity Framework中查找具有组合键的实体

[英]How to find entity with composite key in Entity Framework

I have an existing database on which I am using code-first EF. 我有一个现有的数据库,我使用代码优先EF。 Now the database has a table with a composite key. 现在数据库有一个带有复合键的表。 I define this table in the code as follows 我在代码中定义了这个表,如下所示

public class AssessmentResultType
{
    [Key]
    [Column(Order=1)]
    public int AssessmentID {get; set;}
    public int ResultType {get; set;}
    [Key]
    [Column(Order=2)]
    public int ResultTypeID {get; set;}
    .....
}

My repository is 我的存储库是

 public class AssessmentResultTypeRespository : Repository<AssessmentResultType>
{
    public AssessmentResultTypeRespository(string connString)
        :base(connString)
    { }
}

Repository.cs Repository.cs

public class Repository<TEntity> : IRepository<TEntity> where TEntity:class
{
    protected readonly GradeXpertContext context;

    public Repository(string connString) {
        context = new ge(connString);
    }

    public TEntity Get(int id)
    {
        return context.Set<TEntity>().Find(id);
    }

    public IEnumerable<TEntity> GetAll() { 
        return context.Set<TEntity>().ToList(); 
    }

    public void Add(TEntity entity) {
        context.Set<TEntity>().Add(entity);
    }

    public void AddRange(IEnumerable<TEntity> entities) {
        context.Set<TEntity>().AddRange(entities);
    }

    public void Remove(TEntity entity) {
        context.Set<TEntity>().Remove(entity);
    }

    public void RemoveRange(IEnumerable<TEntity> entities) {
        context.Set<TEntity>().RemoveRange(entities);
    }
}

How do I adjust/override the above code to accept composite key only in case of AssessmentResultType ? 如何在AssessmentResultType情况下调整/覆盖上面的代码以接受复合键? So that I can write 这样我就可以写了

var art1 = repAssResultType.Get(32, 4);

Just change one method: 只需更改一种方法:

public TEntity Get(params object[] keyValues)
{
     return context.Set<TEntity>().Find(keyValues);
}

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM