查找两个列表的所有可能组合

Question

Given two lists of arbitrary length:

list1 = ['a', 'b', 'c']
list2 = ['1', '2', '3']

list1 is the list of objects and list2 is the possible values of each object.How do I find all possible combinations of these two lists (I'm not sure if that's the right terminology)

Expected output:

[
    [('a', '1'), ('b', '1'), ('c', '1')],
    [('a', '1'), ('b', '1'), ('c', '2')],
    [('a', '1'), ('b', '1'), ('c', '3')],
    [('a', '2'), ('b', '1'), ('c', '1')],
    [('a', '2'), ('b', '1'), ('c', '2')],
    [('a', '2'), ('b', '1'), ('c', '3')],
    [('a', '3'), ('b', '1'), ('c', '1')],
    [('a', '3'), ('b', '1'), ('c', '2')],
    [('a', '3'), ('b', '1'), ('c', '3')],
    # etc
]

Answer 1

You can use itertools.product() to get Cartesian product of input iterables, and zip them :

from itertools import product

a = ['a', 'b', 'c']
b = ['1', '2', '3']
print([list(zip(a, p)) for p in product(b,repeat=3)])

Output:

[[('a', '1'), ('b', '1'), ('c', '1')], [('a', '1'), ('b', '1'), ('c', '2')], [('a', '1'), ('b', '1'), ('c', '3')], [('a', '1'), ('b', '2'), ('c', '1')], [('a', '1'), ('b', '2'), ('c', '2')], [('a', '1'), ('b', '2'), ('c', '3')], [('a', '1'), ('b', '3'), ('c', '1')], [('a', '1'), ('b', '3'), ('c', '2')], [('a', '1'), ('b', '3'), ('c', '3')], [('a', '2'), ('b', '1'), ('c', '1')], [('a', '2'), ('b', '1'), ('c', '2')], [('a', '2'), ('b', '1'), ('c', '3')], [('a', '2'), ('b', '2'), ('c', '1')], [('a', '2'), ('b', '2'), ('c', '2')], [('a', '2'), ('b', '2'), ('c', '3')], [('a', '2'), ('b', '3'), ('c', '1')], [('a', '2'), ('b', '3'), ('c', '2')], [('a', '2'), ('b', '3'), ('c', '3')], [('a', '3'), ('b', '1'), ('c', '1')], [('a', '3'), ('b', '1'), ('c', '2')], [('a', '3'), ('b', '1'), ('c', '3')], [('a', '3'), ('b', '2'), ('c', '1')], [('a', '3'), ('b', '2'), ('c', '2')], [('a', '3'), ('b', '2'), ('c', '3')], [('a', '3'), ('b', '3'), ('c', '1')], [('a', '3'), ('b', '3'), ('c', '2')], [('a', '3'), ('b', '3'), ('c', '3')]]