正则表达式从字符串中删除特殊字符

Question

I'm trying to write a regex that only allows letters, numbers, single white spaces, '-' literal, and '/' literal. How do I limit my expression to only these?

If I enter "This should be invalid because it ends with!!! these" , it is still returned as a valid string, even though there's an exclamation at the end.
The one I have is not entirely correct:

[A-Z]|[a-z]|[0-9]|/|\s|-

Answer 1

The problem here is that, by default, regular expressions do not have to match the entire string. One character is sufficient to constitute a match (and sometimes even none)! You need to surround your regex like ^(?: ... )+$ to make it work as you want:

 console.log([ 'This should be invalid because it ends with!!! these', //=> false 'This is valid' //=> true ].map(/ /.test, /^(?:[AZ]|[az]|[0-9]|\\/|\\s|-)+$/ ))

However, a more compact way to write the same expression would be ^[A-Za-z\\d\\s\\/-]+$ .

 console.log([ 'This should be invalid because it ends with!!! these', //=> false 'This is valid' //=> true ].map(/ /.test, /^[A-Za-z\\d\\s\\/-]+$/ ))