Rust编译器用什么算法来推断生命周期变量？

Question

fn foo<'a>(x: &'a i32, y: &'a i32) {}

fn main() { 
    let a = 123;
    {
        let b = 234;
        foo(&a, &b);
    }
}

In the code above &a and &b should hopefully be references with different lifetimes.

How does the compiler infer the lifetime var 'a for foo ? As far as I can tell, it's not using a standard Hindley-Milner unification algorithm. The lifetime must be the inner scope or some intersection of the two lifetimes.

Is lifetime inference a completely separate process to the standard type inference?

Does the compiler use intersection types or use some sub-type relationship between lifetimes to choose the most restricted lifetime?

Answer 1

Rust uses a modified Hindley-Milner unification algorithm because it has sub-typing relationships.

For example, &'static T is a sub-type of &'a T for any 'a .

Your case is relatively easy, when the compiler sees the call foo(&a, &b) it just unifies 'a as the most restrictive of both lifetimes (which is the intersection, since lifetimes are lexical for now).