[英]How to setup firewalls with PUGXMultiUserBundle in security.yml
I just started using PUGXMultiUserBundle I want to have 2 users in the system (Administration, clients) Now I want to have separate admin panels and different redirects after successful logins, registrations, etc.. 我刚开始使用PUGXMultiUserBundle,我想在系统中拥有2个用户(管理,客户端)。现在,我想拥有独立的管理面板和成功登录,注册后的不同重定向。
Shouldn't I be able to setup firewalls in my security.yml based on the userdiscrimination? 我是否应该基于用户区分在我的security.yml中设置防火墙?
Now that I followed the instructions and figured out how to build the registration form, and my users are separated. 现在,我按照说明进行操作,并弄清楚如何构建注册表单,并且我的用户已经分开。 When the registration is complete I get an error on the confirmed url
注册完成后,我在确认的网址上收到错误消息
There is no user provider for user "AppBundle\\Entity\\CabAgencyUser".
Sorry for my poor english, but your solution maybe this: 对不起,我的英语不好,但是您的解决方案可能是这样的:
Declare two services like this in app/config/services.yml or some other service.yml inside any bundle (AppBundle for example): 在app / config / services.yml或任何捆绑包(例如AppBundle)内的其他service.yml中声明两个这样的服务:
app_user_security.component.authentication.handler.login_success_handler:
class: AdminBundle\Component\Authentication\Handler\LoginSuccessHandler
arguments: [@router, @security.context]
tags:
- { name: 'monolog.logger', channel: 'security' }
app_user_security.component.authentication.handler.logout_success_handler:
class: AdminBundle\Component\Authentication\Handler\LogoutSuccessHandler
arguments: [@router]
tags:
- { name: 'monolog.logger', channel: 'security' }
Next create two class like this: 接下来创建两个这样的类:
<?php
/**
* Handler for users Login
*/
namespace AdminBundle\Component\Authentication\Handler;
use Symfony\Component\HttpFoundation\Cookie;
use Symfony\Component\Security\Http\Authentication\AuthenticationSuccessHandlerInterface;
use Symfony\Component\Security\Core\Authentication\Token\TokenInterface;
use Symfony\Component\Security\Core\SecurityContext;
use Symfony\Component\HttpFoundation\Request;
use Symfony\Component\HttpFoundation\RedirectResponse;
use BeSimple\I18nRoutingBundle\Routing\Router;
class LoginSuccessHandler implements AuthenticationSuccessHandlerInterface {
protected $router;
protected $security;
function __construct(Router $router, SecurityContext $security)
{
$this->router = $router;
$this->security = $security;
}
public function onAuthenticationSuccess(Request $request, TokenInterface $token)
{
$session = $request->getSession();
$obj = array();
$obj['name'] = $token->getUser()->__toString();
$obj['username'] = $token->getUsername();
$session->set('last_login_user', $obj);
if ($this->security->isGranted('ROLE_SUPER_ADMIN') || $this->security->isGranted('ROLE_ADMINISTRADOR'))
{
$referer_url = $this->router->generate('admin_dashboard');
}
elseif($this->security->isGranted('ROLE_USUARIO') || $this->security->isGranted('ROLE_USUARIO_SOCIAL')) {
$referer_url = $this->router->generate('app_frontend_dashboard', array(
//'slug' => $token->getUser()->getSlug()
));
} else {
$referer_url = $this->router->generate('app_frontend_dashboard');
}
$cookie = new Cookie('last_login_user', serialize($token->getUser()), time()+(3600*48));
$response = new RedirectResponse($referer_url);
$response->headers->setCookie($cookie);
return $response;
}
}
and this: 和这个:
<?php
/**
* Handler for logout...
*/
namespace AdminBundle\Component\Authentication\Handler;
use Symfony\Component\Security\Http\Logout\LogoutSuccessHandlerInterface;
use Symfony\Component\Security\Core\Authentication\Token\TokenInterface;
use Symfony\Component\HttpFoundation\Request;
use Symfony\Component\HttpFoundation\RedirectResponse;
use BeSimple\I18nRoutingBundle\Routing\Router;
class LogoutSuccessHandler implements LogoutSuccessHandlerInterface {
protected $router;
public function __construct(Router $router)
{
$this->router = $router;
}
public function onLogoutSuccess(Request $request)
{
// redirect the user to where they were before the login process begun.
//$referer_url = $request->headers->get('referer');
//$response = new RedirectResponse($referer_url);
$referer_url = $this->router->generate('app_frontend_homepage');
$response = new RedirectResponse($referer_url);
return $response;
}
}
Good luk ! 祝你好运!
I solve the problem of No user provider with chained providers like this: 我用这样的链接提供程序解决了没有用户提供程序的问题:
//security.yml
security:
encoders:
#FOS\UserBundle\Model\UserInterface: bcrypt
FOS\UserBundle\Model\UserInterface: sha512
role_hierarchy:
ROLE_ADMINISTRADOR: [ROLE_USUARIO, ROLE_USUARIO_SOCIAL]
ROLE_SUPER_ADMINISTRADOR: ROLE_ADMINISTRADOR
# http://symfony.com/doc/current/security.html#b-configuring-how-users-are-loaded
providers:
chain_provider:
chain:
providers: [in_memory, fos_userbundle, user_db_username, user_db_email]
in_memory:
memory: ~
fos_userbundle:
id: fos_user.user_provider.username_email
user_db_username:
entity: { class: AdminBundle\Entity\UsuarioBase, property: username }
user_db_email:
entity: { class: AdminBundle\Entity\UsuarioBase, property: email }
I think just now, why have some level of incompatibility with FOSUserBundle and PUXMultiuserBundle, some thinks working time ago, now are brokens ! 我想刚才,为什么与FOSUserBundle和PUXMultiuserBundle有某种程度的不兼容,有人认为工作时间以前,现在坏了!
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