循环进入python中的向量列表

Question

Given a list of sentences I am trying to do in a short way, get from a list the strings from a structure(list of vectors) in which the first position is the value of the string:

sentence_list = ['I want this',' It hurts','Life is too short as it is' ]

structure = [(1,'I want this. Not that. Right now.'), (2,'When I think about what you are doing, I wonder if you realize the effect you are having on me. It hurts. A lot.'),(3,'Life is too short as it is. In short, she had a cushion job.')]

The result would be a list with the values of the position 0 of the vector.

My first try:

result = []
    for s in sentence_list:
        for i in structure:
            if s in i[1].split('.'):
                    result.append(i[0])

The Target is to improve it in a way to do it in a simple line.

result
[1, 2, 3] # the result is giving the first value of the vector if the string is there..

Answer 1

If the question is "how do I make it a one-liner" then the answer is:

result = [index for index, target in structure for sentence in sentence_list if sentence in target.split('.')]

but that doesn't make the code much more readable.