循環進入python中的向量列表

Question

給定我要用簡短的方式列出的句子列表，從列表中獲取結構（向量列表）中的字符串，其中第一個位置是字符串的值：

sentence_list = ['I want this',' It hurts','Life is too short as it is' ]

structure = [(1,'I want this. Not that. Right now.'), (2,'When I think about what you are doing, I wonder if you realize the effect you are having on me. It hurts. A lot.'),(3,'Life is too short as it is. In short, she had a cushion job.')]

結果將是帶有向量位置0值的列表。

我的第一次嘗試：

result = []
    for s in sentence_list:
        for i in structure:
            if s in i[1].split('.'):
                    result.append(i[0])

目標是通過一種簡單的方式來改進它。

result
[1, 2, 3] # the result is giving the first value of the vector if the string is there..

Answer 1

如果問題是“我如何使其成為單線”，那么答案是：

result = [index for index, target in structure for sentence in sentence_list if sentence in target.split('.')]

但這並不能使代碼更具可讀性。