从一个文件中打开多个文件

Question

I need to open a file that have multiple absolute file directories.

EX:

Layer 1 = C:\\User\\Files\\Menu\\Menu.snt

Layer 2 = C:\\User\\Files\\N0 - Vertical.snt

The problem is that when I try to open C:\\User\\Files\\Menu\\Menu.snt python doesn't like \\U or \\N

I could open using r"C:\\User\\Files\\Menu\\Menu.snt" but I can't automate this process.

file = open(config.txt, "r").read()
list = []

for line in file.split("\n"):
    list.append(open(line.split("=",1)[1]).read())

It prints out:

SyntaxError: (unicode error) 'unicodeescape' codec can't decode bytes in position 33-34: malformed \N character escape

Answer 1

The backslash character \\ is used as an escape character by the Python interpreter in order to provide special characters.

For example, \\n is a "New Line" character, like you would get from pressing the Return key on your keyboard.

So if you are trying to read something like newFolder1\\newFolder2 , the interpreter reads it as:

newFolder1
ewFolder2

where the New Line character has been inserted between the two lines of text.

You already mentioned one workaround: using raw strings like r'my\\folder\\structure' and I'm a little curious why this can't be automated.

If you can automate it, you could try replacing all instances of a single backslash ( \\ ) with a double backslash ( \\\\ ) in your file paths and that should work.

Alternatively, you can try looking in the os module and dynamically building your paths using os.path.join() , along with the os.sep operator.

One final point: You can save yourself some effort by replacing:

list.append(open(line.split("=",1)[1]).read())

by

list = open(line.split("=",1)[1]).readlines()

Answer 2

here is my solution:

file = open("config.txt", "r").readlines()
list = [open(x.split("=")[1].strip(), 'r').read() for x in file]

readlines creates a list that contains all lines in file, there is no need to split the whole string.