将列表中的字符串转换为float

Question

this issue is driving me nuts. I have a scrapped data from a website and put those data into a dictionary. As a result I have a couple of lists and one of those lists looks like this:

    'In': ['7,051,156,075,145', '878,009,569,197', '427,386,441,994', '278,189,230,134', '230,599,954,634', '197,088,252,840', '101,610,549,933', '78,426,830,219', '80,925,933,532', '58,451,193,176', '55,701,282,247', '49,748,756,546', '48,642,591,960', '45,686,162,172', '44,227,235,911', '40,467,951,256', '16,392,881,465', '5,988,546,624', '41,810,356,569', '23,515,110,330', '35,815,116,718', '10,968,016,226', '518,858,345', '29,947,210,177', '29,030,975,280', '28,803,225,552', '373,570,428', '27,527,784,709', '373,964,822', '514,671,410', '25,875,702,735', '416,462,736', '24,423,209,779', '24,332,893,924', '22,491,450,198', '22,894,037,015', '23,026,866,310', '6,148,324,700', '22,226,875,309', '21,127,010,221', '375,662,568', '18,845,330,059', '238,084,409', '18,338,638,037', '6,469,472,952', '16,988,637,757', '234,705,103', '16,164,528,769', '236,542,082', '15,878,894,181', '15,892,415,892', '384,601,333', '173,719,914', '14,374,301,195', '13,789,745,661', '13,333,600,469', '12,935,822,692', '1,414,494,923', '13,000,908,688', '2,875,324,761', '280,912,611', '12,443,874,812', '12,470,333,848', '188,668,181', '12,092,658,438', '676,583,644', '11,997,025,285', '11,677,854,811', '220,087,430', '11,251,777,539', '11,442,705,899', '8,628,429,553', '190,648,851', '11,187,421,523', '3,684,540,569', '10,670,576,444', '10,740,578,885', '10,582,331,778', '10,557,152,315', '9,804,556,177', '10,325,762,681', '10,193,777,314', '10,241,020,644', '10,218,671,348', '5,565,872,689', '6,066,496,977', '128,971,640', '160,853,134', '3,061,365,095', '8,849,393,167', '182,484,904', '161,406,328', '9,335,264,956', '158,941,175', '8,893,005,099', '132,642,660', '147,492,645', '133,898,533', '8,565,414,335', '8,543,285,361', '1,081,514,186', '8,010,900,010', '344,032,888', '7,851,320,645', '119,252,217', '7,708,770,926', '3,831,828,937', '266,060,360', '7,469,255,927', '2,553,584,433', '7,404,456,294', '1,775,993,183', '7,338,693,939', '7,337,702,662', '7,246,023,792', '3,147,875,441', '142,555,296', '1,953,694,528', '3,918,267,288', '1,324,557,844', '5,683,622,890', '6,927,422,982', '106,687,337', '6,912,850,849', '2,845,801,508', '6,818,774,192', '6,853,915,064', '147,347,763', '344,146,667', '6,711,901,497', '6,570,349,311', '6,519,300,790', '135,371,330', '6,472,184,188', '84,726,075', '6,224,918,718', '5,795,088,428', '5,348,330,674', '76,438,957', '6,156,100,475', '6,046,328,039', '1,572,859,369', '5,966,535,367', '5,960,854,825', '5,844,987,758', '99,526,367', '3,320,692,742', '5,763,785,447', '332,891,989', '5,673,010,795', '2,120,698,374', '5,600,425,762', '3,406,789,774']

The values have been stored as strings which I think could be directly converted to floats but I dont know how. Nevermind, I thought I could just convert those values into floats and work with them further. However I cant get it to work. I assigned the list to the variable "bob" and tried the following code to convert to float:

empty = []
der = np.array(empty, dtype = np.float32)
der = np.append(der, bob)

When i try

print(der/2)

it gives me this: "TypeError: ufunc 'true_divide' not supported for the input types, and the inputs could not be safely coerced to any supported types according to the casting rule ''safe''"

whats going on here? Where is my mistake?

I appreciate any help! Thanks

Answer 1

you can use map and lambda to remove comma and convert the list of string floats to list of floats

result = list(map(lambda x: float(x.replace(",", "")), list_of_string_floats))

for integers it would be

result = list(map(lambda x: int(x.replace(",", "")), list_of_string_ints))

There is no need to use numpy

Answer 2

You first have to get rid of the ",".

s = '7,051,156,075,145'
f = float(s.replace(',',''))

After this, f is the float value of the given string.

For the whole thing, you can do this:

float_list = [float(s.replace(',','')) for s in string_list]

Answer 3

如果L是您的原始列表，则可读性最高：

[[float(x) for x in s.split(',')] for s in L ]  

Answer 4

check if that works

print map(lambda x: float("".join(x.split(","))), a)

https://repl.it/H6ZL