[英]Convert a list of strings to either int or float
I have a list which looks something like this: 我有一个看起来像这样的列表:
['1', '2', '3.4', '5.6', '7.8']
How do I change the first two to int
and the three last to float
? 如何将前两个更改为
int
,最后三个更改为float
?
I want my list to look like this: 我希望我的列表看起来像这样:
[1, 2, 3.4, 5.6, 7.8]
Use a conditional inside a list comprehension 在列表理解中使用条件
>>> s = ['1', '2', '3.4', '5.6', '7.8']
>>> [float(i) if '.' in i else int(i) for i in s]
[1, 2, 3.4, 5.6, 7.8]
Interesting edge case of exponentials. 有趣的指数边缘情况。 You can add onto the conditional.
您可以添加到条件。
>>> s = ['1', '2', '3.4', '5.6', '7.8' , '1e2']
>>> [float(i) if '.' in i or 'e' in i else int(i) for i in s]
[1, 2, 3.4, 5.6, 7.8, 100.0]
Using isdigit
is the best as it takes care of all the edge cases (mentioned by Steven in a comment ) 使用
isdigit
是最好的,因为它可以处理所有边缘情况( Steven在评论中提到)
>>> s = ['1', '2', '3.4', '5.6', '7.8']
>>> [int(i) if i.isdigit() else float(i) for i in s]
[1, 2, 3.4, 5.6, 7.8, 100.0]
Use a helper function: 使用辅助函数:
def int_or_float(s):
try:
return int(s)
except ValueError:
return float(s)
Then use a list comprehension to apply the function: 然后使用list comprehension来应用函数:
[int_or_float(el) for el in lst]
Why not use ast.literal_eval
? 为什么不使用
ast.literal_eval
?
import ast
[ast.literal_eval(el) for el in lst]
Should handle all corner cases. 应该处理所有角落案件。 It's a little heavyweight for this use case, but if you expect to handle any Number-like string in the list, this'll do it.
对于这个用例来说,它有点重量级,但是如果你希望在列表中处理任何类似数字的字符串,那么这就行了。
Use isdigit method of string: 使用字符串的isdigit方法:
numbers = [int(s) if s.isdigit() else float(s) for s in numbers]
or with map: 或与地图:
numbers = map(lambda x: int(x) if x.isdigit() else float(x), numbers)
def st_t_onumber(x):
import numbers
# if any number
if isinstance(x,numbers.Number):
return x
# if non a number try convert string to float or it
for type_ in (int, float):
try:
return type_(x)
except ValueError:
continue
l = ['1', '2', '3.4', '5.6', '7.8']
li = [ st_t_onumber(x) for x in l]
print(li)
[1, 2, 3.4, 5.6, 7.8]
If you want to display as the same list append the list by using the following query: 如果要显示为相同的列表,请使用以下查询追加列表:
item = input("Enter your Item to the List: ")
shopList.append(int(item) if item.isdigit() else float(item))
Here when the user enters int values or float values it appends the list shopList and stores these values in it. 这里当用户输入int值或浮点值时,它会附加列表shopList并将这些值存储在其中。
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