使用 Java 8 Stream API 从对象列表中收集列表

Question

I have a class like this

public class Example {
    private List<Integer> ids;

    public getIds() {
        return this.ids; 
    }
}

If I have a list of objects of this class like this

List<Example> examples;

How would I be able to map the id lists of all examples into one list? I tried like this:

List<Integer> concat = examples.stream().map(Example::getIds).collect(Collectors.toList());

but getting an error with Collectors.toList()

What would be the correct way to achive this with Java 8 stream api?

Answer 1

Use flatMap :

List<Integer> concat = examples.stream()
    .flatMap(e -> e.getIds().stream())
    .collect(Collectors.toList());

Answer 2

Another solution by using method reference expression instead of lambda expression:

List<Integer> concat = examples.stream()
                               .map(Example::getIds)
                               .flatMap(List::stream)
                               .collect(Collectors.toList());

Answer 3

您可以使用 flatMap 替代 stream.map