MySql：在两个特定值之间选择行：

Question

I have this table:

and I'd like to select the rows between 'inizio_votazione1' e fine_votazione1'.

I tried this code:

$sql  = "SELECT codice FROM scansioni WHERE codice BETWEEN 'inizio_votazione1' 
AND 'fine_votazione1'";

while ($row = $result->fetch_row()) {
// print_r($row);

$res = $row[0];
echo $res;
echo "<br />";
}

but I see no result.

Which is the correct syntax to retrieve the desired result? Thanks

Answer 1

I don't think you really want to use BETWEEN . That will basically look for alphabetically ordered values that are between those two. I would think you could do something like this:

SELECT codice
FROM scansioni
WHERE id > (SELECT MIN(id) 
            FROM scansioni
            WHERE codice IN ('inizio_votazione1', 'fine_votazione1'))
  AND id < (SELECT MAX(id) 
            FROM scansioni
            WHERE codice IN ('inizio_votazione1', 'fine_votazione1'))

This may not be the most elegant solution, but from what I tried, it worked.

A better option might be to add a separate table that stores the start and end id for each group. Then you could just get the start and end id s for the group you want and then select all the values from scansioni that have id s in the correct range.

Answer 2

尝试这个：

SELECT codice FROM scansioni WHERE codice between 'inizio_votazione1' abd 'fine_votazione1'

Answer 3

Try changing:

$sql  = SELECT codice FROM scansioni WHERE codice BETWEEN 'inizio_votazione1' 
AND 'fine_votazione1';

To:

$sql  = "SELECT codice FROM scansioni WHERE codice BETWEEN 'fine_votazione1' 
AND 'inizio_votazione1'";

BETWEEN uses the sort order to determine the result.

Also, strings need to be quoted in php.

Answer 4

尝试这个：-

SELECT codice FROM `scansioni` WHERE id between (select id from scansioni where codice='inizio_votazione1') and (select id from scansioni where codice='fine_votazione1')