意图从图库中获取图像

Question

I want to get a image from Gallery with the share command.

My current code is:

Intent intent = getIntent();
    String action = intent.getAction();
    String type = intent.getType();

    if (Intent.ACTION_SEND.equals(action) && type != null) {
        Log.d("Test","Simple SEND");
        Uri imageUri = (Uri)intent.getParcelableExtra(Intent.EXTRA_STREAM);
        if (imageUri != null) {
            InputStream iStream = getContentResolver().openInputStream(imageUri);
        }
    } else if (Intent.ACTION_SEND_MULTIPLE.equals(action) && type != null) {
        Log.d("Test", "Multiple SEND");
    }

The value of the imageUri is: content://media/external/images/media/37

But the function "openInputStream" throws the error "java.io.FileNotFoundException".

With the following function i get the real path of the image.

public static String getRealPathFromUri(Context context, Uri contentUri) {
    Cursor cursor = null;
    try {
        String[] proj = { MediaStore.Images.Media.DATA };
        cursor = context.getContentResolver().query(contentUri, proj, null, null, null);
        int column_index = cursor.getColumnIndexOrThrow(MediaStore.Images.Media.DATA);
        cursor.moveToFirst();
        return cursor.getString(column_index);
    } finally {
        if (cursor != null) {
            cursor.close();
        }
    }
}

But i don't know how to convert it to a bitmap.

Answer 1

A Uri is not a File . new File(imageUri.toString()) is always wrong. imageUri.getPath() only works if the scheme of the Uri is file , and in your case, the scheme is probably content .

Use ContentResolver and openInputStream() to get an InputStream on the file or content identified by the Uri . Then, pass that stream to BitmapFactory.decodeStream() .

Also, please decode bitmaps on a background thread, so that you do not freeze your UI while this work is going on.