将__m128i值转换为std :: tuple

Question

Imagine that, after some SIMD calculations, I get a __m128i value with the fourth field with a useless zero value. Is there a simple and portable way to cast the other three fields into a std::tuple<int,int,int> , bearing in mind it is not standard layout ?

Answer 1

Ugly, but portable. I don't believe, that there is fast solution, since std::tuple does not have defined memory layout. So just copying those three values into a tuple.

std::tuple<int, int, int> to_tuple(__m128i& value)
{
    auto* ptr = reinterpret_cast<int*>(&value);
    return std::make_tuple(ptr[0], ptr[1], ptr[2]);
}

---

Why do you need this? Maybe you can get around your problem some other way.