使用格式在python中格式化字符串

Question

There is code:

xor = 127002634777471167503839844242873650079
print '{0:x}'.format(xor)
print format(xor, 'x')

Can anyone explain what two last strings means? How 5f8bd156f9e50e5381ab282ba2000b9f is generated from xor variable?

Answer 1

That's because this is the Hexa representation of your number.

You can set it to .2f (double in normal (fixed-point) notation), for example:

xor = 127002634777471167503839844242873650079
print '{0:.2f}'.format(xor)
print format(xor, '.2f')

Or using .2g (double in either normal or exponential notation, This type differs slightly from fixed-point notation in that insignificant zeroes to the right)

print '{0:.2g}'.format(xor)

You can read more about the type field ( .2f and .3g ) in here