请问如何将来自多个SELECT语句的结果合并到一个结果集中？

Question

Giving below is the schema and the individual select statements. 下面给出的是架构和各个select语句。 However, i want to retrieve all the result of the various queries at ones. 但是，我想检索各种查询的所有结果。 I if 我如果

//SCHEMA.. here is the db schema // SCHEMA ..这是数据库模式

CREATE TABLE `orgs` (

  `id` int(10) UNSIGNED NOT NULL AUTO_INCREMENT PRIMARY KEY,
  `org_name` varchar(250) NOT NULL,
  UNIQUE (org_name)
)



CREATE TABLE `orgs_relation` (

  `org_id` int(10) UNSIGNED NOT NULL,
  `parent_org_id` int(10) UNSIGNED NOT NULL,
  CONSTRAINT org_relation_pair UNIQUE (org_id, parent_org_id)
)


#// Get parents
SELECT parent_org_id, orgs.org_name as org_name, "parent" as parent FROM `orgs_relation`
JOIN orgs ON orgs_relation.parent_org_id = orgs.id
WHERE org_id = (SELECT id FROM orgs WHERE org_name='Black Banana')
ORDER BY org_name ASC

#// Get chidren
SELECT org_id, orgs.org_name as org_name, "children" as children FROM `orgs_relation`
JOIN orgs ON orgs_relation.org_id = orgs.id
WHERE parent_org_id = (SELECT id FROM orgs WHERE org_name='Black Banana')
ORDER BY org_name ASC

#// Get sisters
SELECT DISTINCT or2.org_id AS sister_id, org_name, "sisters" as sisters FROM `orgs_relation` AS or1
JOIN orgs_relation AS or2 ON or1.parent_org_id = or2.parent_org_id
JOIN orgs ON or2.org_id = orgs.id
WHERE or1.org_id = (SELECT id FROM orgs WHERE org_name='Black Banana')
ORDER BY org_name ASC

I am currently using the method below and it's not working: 我目前正在使用以下方法，但无法正常工作：

app.get("/api/orgs/all/:id", function(req, res){
    var p = req.params.id;
    console.log(p);

var daughtersQuery = "SELECT org_id, orgs.org_name as org_name, 'daughters' as daughters FROM `orgs_relation` JOIN orgs ON orgs_relation.org_id = orgs.id  WHERE parent_org_id = (SELECT id FROM orgs WHERE org_name =  'Black Banana')";
var parentQuery = "SELECT parent_org_id, orgs.org_name as org_name, 'parent' as parent FROM `orgs_relation`JOIN orgs ON orgs_relation.parent_org_id = orgs.id WHERE org_id = (SELECT id FROM orgs WHERE org_name= 'Black Banana')";   
var sistersQuery = "SELECT DISTINCT or2.org_id AS sister_id, org_name, 'sisters' as sisters FROM `orgs_relation` AS or1 JOIN orgs_relation AS or2 ON or1.parent_org_id = or2.parent_org_id JOIN orgs ON or2.org_id = orgs.id WHERE or1.org_id = (SELECT id FROM orgs WHERE org_name= 'Black Banana')";

   var q = "SELECT DISTINCT id, org_name, org_id, parent_org_id from (" +
                        daughtersQuery + " UNION ALL " +
                        parentQuery + " UNION ALL " +
                        sistersQuery + " ) a ORDER ALL org_name asc";
      //  console.log(q);

         connection.query(q, function (error, results) {
              if (error) throw error;
          // console.log(results);
          res.send(results);
        });
});

Answer 1

I assume you are using node-mysql . 我假设您正在使用node-mysql 。 The docs state: 文档状态：

Support for multiple statements is disabled for security reasons (it allows for SQL injection attacks if values are not properly escaped). 出于安全原因，禁用了对多条语句的支持（如果值未正确转义，则允许进行SQL注入攻击）。

Multiple statement queries 多条语句查询

To use this feature you have to enable it for your connection: 要使用此功能，必须为连接启用它：

var connection = mysql.createConnection({multipleStatements: true});

Once enabled, you can execute queries with multiple statements by separating each statement with a semi-colon ; 启用后，您可以通过用分号分隔每个语句来对多个语句执行查询; . 。 Result will be an array for each statement. 结果将是每个语句的数组。

Example 例

connection.query('SELECT ?; SELECT ?', [1, 2], function(err, results) {
  if (err) throw err;

  // `results` is an array with one element for every statement in the query:
  console.log(results[0]); // [{1: 1}]
  console.log(results[1]); // [{2: 2}]
});