please how can i combine the result from this multiple SELECT statements into a single result set?

Question

Giving below is the schema and the individual select statements. However, i want to retrieve all the result of the various queries at ones. I if

//SCHEMA.. here is the db schema

CREATE TABLE `orgs` (

  `id` int(10) UNSIGNED NOT NULL AUTO_INCREMENT PRIMARY KEY,
  `org_name` varchar(250) NOT NULL,
  UNIQUE (org_name)
)



CREATE TABLE `orgs_relation` (

  `org_id` int(10) UNSIGNED NOT NULL,
  `parent_org_id` int(10) UNSIGNED NOT NULL,
  CONSTRAINT org_relation_pair UNIQUE (org_id, parent_org_id)
)


#// Get parents
SELECT parent_org_id, orgs.org_name as org_name, "parent" as parent FROM `orgs_relation`
JOIN orgs ON orgs_relation.parent_org_id = orgs.id
WHERE org_id = (SELECT id FROM orgs WHERE org_name='Black Banana')
ORDER BY org_name ASC

#// Get chidren
SELECT org_id, orgs.org_name as org_name, "children" as children FROM `orgs_relation`
JOIN orgs ON orgs_relation.org_id = orgs.id
WHERE parent_org_id = (SELECT id FROM orgs WHERE org_name='Black Banana')
ORDER BY org_name ASC

#// Get sisters
SELECT DISTINCT or2.org_id AS sister_id, org_name, "sisters" as sisters FROM `orgs_relation` AS or1
JOIN orgs_relation AS or2 ON or1.parent_org_id = or2.parent_org_id
JOIN orgs ON or2.org_id = orgs.id
WHERE or1.org_id = (SELECT id FROM orgs WHERE org_name='Black Banana')
ORDER BY org_name ASC

I am currently using the method below and it's not working:

app.get("/api/orgs/all/:id", function(req, res){
    var p = req.params.id;
    console.log(p);

var daughtersQuery = "SELECT org_id, orgs.org_name as org_name, 'daughters' as daughters FROM `orgs_relation` JOIN orgs ON orgs_relation.org_id = orgs.id  WHERE parent_org_id = (SELECT id FROM orgs WHERE org_name =  'Black Banana')";
var parentQuery = "SELECT parent_org_id, orgs.org_name as org_name, 'parent' as parent FROM `orgs_relation`JOIN orgs ON orgs_relation.parent_org_id = orgs.id WHERE org_id = (SELECT id FROM orgs WHERE org_name= 'Black Banana')";   
var sistersQuery = "SELECT DISTINCT or2.org_id AS sister_id, org_name, 'sisters' as sisters FROM `orgs_relation` AS or1 JOIN orgs_relation AS or2 ON or1.parent_org_id = or2.parent_org_id JOIN orgs ON or2.org_id = orgs.id WHERE or1.org_id = (SELECT id FROM orgs WHERE org_name= 'Black Banana')";

   var q = "SELECT DISTINCT id, org_name, org_id, parent_org_id from (" +
                        daughtersQuery + " UNION ALL " +
                        parentQuery + " UNION ALL " +
                        sistersQuery + " ) a ORDER ALL org_name asc";
      //  console.log(q);

         connection.query(q, function (error, results) {
              if (error) throw error;
          // console.log(results);
          res.send(results);
        });
});

Answer 1

I assume you are using node-mysql . The docs state:

Support for multiple statements is disabled for security reasons (it allows for SQL injection attacks if values are not properly escaped).

Multiple statement queries

To use this feature you have to enable it for your connection:

var connection = mysql.createConnection({multipleStatements: true});

Once enabled, you can execute queries with multiple statements by separating each statement with a semi-colon ; . Result will be an array for each statement.

Example

connection.query('SELECT ?; SELECT ?', [1, 2], function(err, results) {
  if (err) throw err;

  // `results` is an array with one element for every statement in the query:
  console.log(results[0]); // [{1: 1}]
  console.log(results[1]); // [{2: 2}]
});