如何将此MySQL查询转换为等效的Laravel 5.4 Elequent / query builder查询？

Question

SELECT `id` FROM `jobs` WHERE `job_type` IN ( 'topemployercheckbox1','topemployercheckbox2') OR `job_category` IN ( 'Contract','Intern') ;

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我需要将此MySQL查询转换为laravel 5.4查询生成器查询。

Answer 1

you can do

ModelName::whereIn('job_type',['topemployercheckbox1','topemployercheckbox2'])
    ->orwhere(function($q){
          $q->whereIn('job_category',['Contract','Intern'])
})->get('id');

or

ModelName::whereIn('job_type',['topemployercheckbox1','topemployercheckbox2'])
    ->whereIn('job_category',['Contract','Intern'],'or')->get('id');

Answer 2

You can use union of two whereIn query.

$query1= \DB::table("jobs")select("id")->whereIn("job_type",['topemployercheckbox1','topemployercheckbox2']);
$query2=\DB::table("jobs")select("id")->whereIn("job_category",['Contract','Intern']);
$job_ids= $query1->union($query2)->get();

Answer 3

Your query would be like as below. Here we have considered your model name is as Job.

 Job::select('id')
    ->whereIn('job_type',['topemployercheckbox1','topemployercheckbox2'])
    ->orWhereIn('job_category',['Contract','Intern'])
    ->get();