[英]date format when plotting a time series in R
My data frame df
is a daily time series with Datum
and Opbrengst
variables. 我的数据框
df
是包含Datum
和Opbrengst
变量的每日时间序列。 The Datum
variable is between 20160101
to 20170521
. Datum
变量介于20160101
至20170521
之间。
Datum Opbrengst
1 20160101 40609276
2 20160102 79381098
3 20160103 114653269
4 20160104 126044535
5 20160105 180472785
...
I want to do the prediction, so the first thing I do is plot the series to see if the series is stationary or not (if it has seasonality). 我想进行预测,所以我要做的第一件事是绘制序列,以查看序列是否稳定(如果具有季节性)。
However, the date variable is numeric
, so when I plot the series, 但是,date变量是
numeric
,所以当我绘制序列时,
ggplot(data=df, aes(x=Datum , y=Opbrengst, group=1)) +
geom_line()+
geom_point()
it becomes like this: 它变成这样:
The problem is that the series crosses years, that's why R just treats it as a numeric series
, not time series
. 问题在于该序列跨越了多年,这就是为什么R只是将其视为
numeric series
,而不是time series
。
I tried to convert it to dates by using the method from this website 我试图通过使用此网站上的方法将其转换为日期
df$Datum = as.Date(df$Datum)
but the result is incorrect: 但结果不正确:
"57166-06-26" "57166-06-27" "57166-06-28" "57166-06-29" "57166-06-30" "57166-07-01"
My questions are: 我的问题是:
How do I change the datum variable to the date format so that I won't have a problem when I plot the graph? 如何将datum变量更改为日期格式,以便在绘制图形时不会出现问题? Because later I will do need to do both
daily
and weekly
predictions. 因为稍后我将需要做
daily
和weekly
预测。
I know if I use plot.ts()
, then I don't need to change the time format. 我知道如果我使用
plot.ts()
,那么我不需要更改时间格式。 Can I also do the time series plot in ggplot
? 我也可以在
ggplot
绘制时间序列图吗?
[edit] [编辑]
This is the a sample of the data: 这是数据示例:
df <- structure(list(Datum = 20160101:20160120, Opbrengst = c(40609276,
79381098, 114653269, 126044535, 180472785, 169286880, 149272135,
133645566, 70171285, 150029065, 149172032, 107843808, 138196732,
136460905, 133595660, 61716435, 137309503, 193201850, 140766980,
129859068)), .Names = c("Datum", "Opbrengst"), row.names = c(NA,
20L), class = "data.frame")
[Edit] [编辑]
Changed %M
to %m
已将
%M
更改为%m
There are many ways to do this. 有很多方法可以做到这一点。 Three easy ones:
三个简单的:
df <- structure(list(Datum = 20160101:20160120, Opbrengst = c(40609276, 79381098, 114653269, 126044535, 180472785, 169286880, 149272135, 133645566, 70171285, 150029065, 149172032, 107843808, 138196732, 136460905, 133595660, 61716435, 137309503, 193201850, 140766980, 129859068)), .Names = c("Datum", "Opbrengst"), row.names = c(NA, 20L), class = "data.frame")
# 1. Using the as.Date function (as sugges5ted by @SBista) to create a date object:
df$Datum <- as.Date.character(df$Datum, format = "%Y %m %d")
# 2. Or create a POSIXct object:
# df$Datum <- strptime(df$Datum, format = "%Y %m %d")
# 3. Using 'lubridate' to create a Date or POSIXct object (see 'tz' argument in ?ymd):
# df$Datum <- lubridate::ymd(df$Datum, tz = NULL)
ggplot(data=df, aes(x=Datum , y=Opbrengst)) +
geom_line()+
geom_point()
Results in: 结果是:
The problem with your example is that you weren't providing the 'format' argument, so R didn't know that it was year-month-day. 您的示例的问题在于您没有提供'format'参数,因此R不知道它是年月日。
The issue here is the conversion of df$Datum
to class Date
. 这里的问题是
df$Datum
到Date
类的转换。 It has nothing to do with ggplot2
与
ggplot2
Creating sample data as integer
including New Year: 将样本数据创建为包括新年在内的
integer
:
(Datum <- c(20151224:20151231, 20160101:20160107))
[1] 20151224 20151225 20151226 20151227 20151228 20151229 20151230 20151231 20160101
[10] 20160102 20160103 20160104 20160105 20160106 20160107
anytime::anydate()
and lubridate::ymd()
seem to be able to convert integer Datum
directly without coercion to character
. anytime::anydate()
和lubridate::ymd()
似乎能够直接将整数Datum
转换而无需强制转换为character
。
anytime::anydate(Datum)
# [1] "2015-12-24" "2015-12-25" "2015-12-26" "2015-12-27" "2015-12-28" "2015-12-29"
# [7] "2015-12-30" "2015-12-31" "2016-01-01" "2016-01-02" "2016-01-03" "2016-01-04"
#[13] "2016-01-05" "2016-01-06" "2016-01-07"
lubridate::ymd(Datum)
# [1] "2015-12-24" "2015-12-25" "2015-12-26" "2015-12-27" "2015-12-28" "2015-12-29"
# [7] "2015-12-30" "2015-12-31" "2016-01-01" "2016-01-02" "2016-01-03" "2016-01-04"
#[13] "2016-01-05" "2016-01-06" "2016-01-07"
as.Date()
throws errors here: as.Date()
在此处引发错误:
as.Date(Datum)
#Error in as.Date.numeric(Datum) : 'origin' must be supplied
as.Date(Datum, "%Y%m%d")
#Error in charToDate(x) :
# character string is not in a standard unambiguous format
Datum
needs to be coerced to character
first: Datum
必须强制为character
首位:
as.Date(as.character(Datum), "%Y%m%d")
# [1] "2015-12-24" "2015-12-25" "2015-12-26" "2015-12-27" "2015-12-28" "2015-12-29"
# [7] "2015-12-30" "2015-12-31" "2016-01-01" "2016-01-02" "2016-01-03" "2016-01-04"
#[13] "2016-01-05" "2016-01-06" "2016-01-07"
Note that the format string is "%Y%m%d"
with a lowercase m
not "%Y%M%d"
with a capital M
. 需要注意的是格式字符串
"%Y%m%d"
以小写m
不是 "%Y%M%d"
与资本M
。 Interestingly, "%Y %m %d"
with blanks interspersed seems to be working as well, here. 有趣的是,这里插入了带空格的
"%Y %m %d"
似乎也起作用。
# create data
df <- data.frame(
Datum = c(20151220:20151231, 20160101:20160108),
Opbrengst = c(40609276, 79381098, 114653269, 126044535, 180472785, 169286880,
149272135, 133645566, 70171285, 150029065, 149172032, 107843808,
138196732, 136460905, 133595660, 61716435, 137309503, 193201850,
140766980, 129859068))
# coerce to class Date
df$Datum <- anytime::anydate(df$Datum)
library(ggplot2)
ggplot(df, aes(Datum, Opbrengst)) + geom_line() + geom_point()
Note that the gap over New Year has gone. 请注意,新年的差距已经消失。
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