正则表达式删除所有数字和特殊字符，但空格和字母

Question

Can someone help me out with the regular expression to strip a string like this ->

      '226710': 'Kevin Werbach'

to obtain just --> Kevin Werbach

My attempt -->

   instructors = re.sub(r'([^a-zA-Z\s]+?)', '', instructors)

which returned -->

  KevinWerbach  

without any space between.

Answer 1

This works:

import re
text = "'226710': 'Kevin Werbach'"
print(re.sub (r'([^a-zA-Z ]+?)', '', text))

You can also change the space to \\s:

print(re.sub (r'([^a-zA-Z\s]+?)', '', text))