正则表达式：获取以特定字母开头的所有数字和特殊字符，当数字后出现空格时停止

Question

I have this text example:

LALL - 4302 is broken, while LALL-4301 and LALL 3305 are being fixed.

I want to capture:

LALL - 4302, LALL-4301, LALL 3305

I see the pattern as it starts with " LALL " and captures the following numbers, special characters, and spaces, then stops once the number is followed by space.

How can I do it using RegEx?

Answer 1

You may try using re.findall :

inp = "LALL - 4302 is broken, while LALL-4301 and LALL 3305 are being fixed."
matches = re.findall(r'\bLALL\s*-?\s*\S+', inp)
print(matches)

This prints:

['LALL - 4302', 'LALL-4301', 'LALL 3305']