在 Python pandas 中使用正则表达式查找组合数字和字母的特定字符序列

Question

I am trying to find all rows in a pandas DataFrame for which the column col takes values of the format 1234-XX-YYY , where XX is a placeholder for any two capital letters (AZ) and YYY is a placeholder for any three numbers [0-9].

Here is my code so far

How can I achieve the desired result?

df[df['col'].str.contains('^1234-\[A-Z]{2}\[d]{3}', na=False)]

Answer 1

When you escape an open [ you tell the regex engine to match it as a literal character. If you expect a - to appear at some place in the string, you need to add it to the pattern. Also, if you expect uppercase letters to appear, you need AZ , not az .

Use

^1234-[A-Z]{2}-[0-9]{3}$

Details

• ^ - start of string
• 1234- - a literal string
• [AZ]{2} - two uppercase letters
• - - a hyphen
• [0-9]{3} - three digits
• $ - end of string.