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Java流API - 避免使用相同的谓词两次来计算平均值

[英]Java stream API - avoid using same predicate twice to calculate average

class A {
    double value;
    String key;
}

class B {
    List<A> aList;
}

Given List<B> bList , I want to calculate the average of the value s for a specific key k . 给定List<B> bList ,我想计算特定密钥kvalue s的平均值。 Assume each B can hold only 0 or 1 times an instance of A with key.equals(k) . 假设每个B只能用key.equals(k)保持A的实例的0或1倍。

I figured I could first filter aList , and later extract the value using mapToDouble : 我想我可以先过滤aList ,然后使用mapToDouble提取值:

double average = blist.stream().filter(
    b -> b.aList.stream().anyMatch(
        a -> a.key.equals(k)
    )
).mapToDouble(
    b -> b.aList.stream().filter(
        a -> a.key.equals(k)
    ).findFirst().get().value
).average().orElse(0);

But there is clearly a redundancy here, since I am filtering the same list by the same predicate twice ( a -> a.key.equals(k) ). 但是这里显然有一个冗余,因为我用相同的谓词过滤相同的列表两次( a -> a.key.equals(k) )。

Is there a way to mapToDouble while omitting elements with missing matching key s at the same time? 有没有办法mapToDouble同时省略缺少匹配key s的元素?

Edit: 编辑:

Here is a more concrete example, hopefully it will make it easier to understand: 这是一个更具体的例子,希望它更容易理解:

String courseName;

...

double average = students.stream().filter(
    student -> student.getGrades().stream().anyMatch(
        grade -> grade.getCourseName().equals(courseName)
    )
).mapToDouble(
    student -> student.getGrades().stream().filter(
        grade -> grade.getCourseName().equals(courseName)
    ).findFirst().get().getValue()
).average().orElse(0);

System.out.println(courseName + " average: " + average);

Try this: 尝试这个:

double average = bList.stream()
        .flatMap(b -> b.aList.stream())
        .filter(a -> a.key.equals(k))
        .mapToDouble(a -> a.value)
        .average()
        .orElse(Double.NaN);

If your objects have private field and getters, which they really should, it'd be like this: 如果你的对象有私有字段和getter,他们真的应该这样,它就像这样:

double average = bList.stream()
        .map(B::getaList)
        .flatMap(List::stream)
        .filter(a -> a.getKey().equals(k))
        .mapToDouble(A::getValue)
        .average()
        .orElse(Double.NaN);

Try this. 尝试这个。

double average = blist.stream()
    .map(b -> b.aList.stream()
        .filter(a -> a.key.equals(k))
        .findFirst())
    .filter(a -> a.isPresent())
    .mapToDouble(a -> a.get().value)
    .average().orElse(0);

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