[英]Python : Comparing file name with folder name in same directory
I have a folder with lot of zip files and the extracted folders for the same. 我有一个包含很多zip文件的文件夹,并且提取了相同的文件夹。 The folder has become so much clustered .
该文件夹已成簇。
Is there any way to compare the zipped files name with the EXTRACTED folders name in the same directory ? 有什么方法可以将压缩文件名与同一目录中的EXTRACTED文件夹名进行比较?
i want to delete the EXTRACTED folders if they have a .zip file in the same directory. 我要删除EXTRACTED文件夹,如果它们在同一目录中有一个.zip文件。
Hope it help 希望对你有帮助
import os
import shutil
for file in os.listdir(path_to_dir):
if os.path.isdir(file + ".zip"):
shutil.rmtree(file)
You can try something like this: 您可以尝试如下操作:
import shutil
from os import listdir
from os.path import isfile, join, isdir
directories = [d for d in listdir('./') if isdir(join('./', d))]
files = [f for f in listdir('./') if isfile(join('./', f)) and '.zip' in f]
# print(directories)
# print(files)
for d in directories:
for f in files:
if f == d + '.zip':
shutil.rmtree(d)
Note that you need to use something like shutil.rmtree(d)
if you directories contain subdirectories and/or files. 请注意,如果目录包含子目录和/或文件,则需要使用
shutil.rmtree(d)
类的东西。
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