使用-replace从csv的单元格中删除带有特殊字符的字符串

Question

I have a CSV file like:

"localpath"
"C:\Users\calabresel"
"C:\Users\goslinep"
"C:\Users\deangelisr"
"C:\Users\bannont"
"C:\Users\goodwind"

I am looking for a way to isolate just the username from each field. I will then query the AD to determine if each user is disabled or enabled. I haven't been able to figure out how to get just the last piece though. My idea was to use -replace to replace the identical string with null like this:

$txt = import-csv paths1.csv | % {$_.localpath = $_.localpath -replace "C:\Users\", ""}

That came back with invalid regular expression pattern errors though which I assumed was a result of the target string containing special characters (the backslashes). I then started looking for a way to get powershell to take the \\ literally instead. That lead me to try this:

$txt = import-csv paths1.csv | % {$_.localpath = $_.localpath -replace [Regex]::Escape("C:\\Users\\"), ""}

and this

$txt = import-csv paths1.csv | % {$_.localpath = $_.localpath -replace "C:\\Users\\", ""}

both of those methods stop the invalid regular expression errors and just return me a fresh line without complaining. however when I print the $txt variable it is empty...

I'm certain I am approaching this problem from the wrong angle and/or with improper syntax but I could use some guidance as I just started working with powershell a week ago.

any help provided would be greatly appreciated.

Answer 1

The following will import the CSV file and then get the leaf of the path. Ie the user name.

$txt = Import-Csv paths1.csv | ForEach-Object { Split-Path $_.localpath -leaf }

If you still want to use your replace method, just take out the $_.localpath = part and it should work.

$txt = Import-Csv C:\@@Scatch\test.csv | % { $_.localpath -replace "C:\\Users\\", ""}

Answer 2

The reason why you aren't getting anything back into $txt is that you update a property of $_ but don't return $_ .

Assuming that you want to use the regex rather than Split-Path

$txt = import-csv C:\temp\test.csv | % {
    $_.localpath = $_.localpath -replace "C:\\Users\\", ""
    $_
}

Or

$txt = import-csv C:\temp\test.csv | % {
    $_.localpath -replace "C:\\Users\\", ""
}

Answer 3

其他解决方案

Get-Content "C:\temp\test.txt" | select @{N="Value";E={$_.split('\')[-1].replace('"', '')}} -Skip 1