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如何替换python中的重复单词(Hangman Game)!

[英]How to replace the repeat word in python (Hangman Game)!

This game now i have solved till the end.But here is 1 more problem that is how can i replace repeat word in string? 这个游戏现在我已经解决了直到最后。但是这里还有一个问题,那就是如何替换字符串中的重复单词? please help me! 请帮我! Thank you. 谢谢。 For example: my customfile inside there is word:"apple" and when hide the word with dashes: "-----" but when i replace in dashes string i can just only replace dash with 1 p:"ap-le" how can i replace dashes with 2p: "apple".My previous post for this program: How do i detect the repeat input in my hangman game (Python)! 例如:我的自定义文件里面有单词:“apple”,当用破折号隐藏单词时:“-----”但是当我用破折号替换字符串时我只能用1 p代替破折号:“ap-le”如何用2p代替破折号:“apple”。我之前的帖子对于这个程序: 我如何检测我的刽子手游戏(Python)中的重复输入! . Here is my code to replace: 这是我要替换的代码:

def getGuessedWord():
    pos = word.index(guessword.lower())
    print(pos)
    global words             
    words = words[:pos]+ guessword.lower() +words[pos+1:]
    print(words)
    return words

My solution to your overall problem of filtering out guessed letters is the following set of functions: 我对滤除猜测字母的整体问题的解决方案是以下一组函数:

guessed_letters = set()
def guess(letter):
    global guessed_letters
    guessed_letters.add(letter)

def filter_letter(letter):
    if letter in guessed_letters:
        return letter
    else:
        return '-'

def filtered(words):
    for word in words:
        output = ''
        for letter in word:
            output += filter_letter(letter)
        yield output

or more compactly: 或者更紧凑:

guessed_letters = set()
def guess(letter):
    global guessed_letters
    guessed_letters.add(letter)

def filter_letter(letter):
    return letter if letter in guessed_letters else '-'

def filtered(words):
    return [''.join(map(filter_letter, word)) for word in words]

such that: 这样:

>>> words = "bubbly water".split()
>>> guess('a')
>>> ' '.join(filtered(words))
'------ -a---'
>>> guess('b')
>>> ' '.join(filtered(words))
'b-bb-- -a---

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