如何仅在字符之前和之后替换空格而不在数字之前和之后替换空格

Question

all i tryed and found, will remove all spaces. But thats not what i want

my string is

 var str = "24 july 2014 12 5";

i want

"24july2014 12 5"

i found this code example

var str = "Paul m'a dit « Bonjour ! »";
str = str.replace(/\s([!:\?…;»])/g, function (el1, el2) {
return ' ' + el2;
}).replace(/(«)\s/g, function (el1, el2) {
return el2 + ' ';
});
console.log(str);

but its not changeable to my problem. maybe i`am too much noob?

Answer 1

You can do this.

 var str = "24 july 2014 12 5"; str = str.replace(/ (?=[az])/g, "").replace(/([az]) /g, "$1"); console.log(str); 

JS doesn't support lookbehinds, so one workaround is to use capturing groups and echo. The other replace is supported by a lookahead.

---

OP, based on your comment, it seems like you also wish to decode URL params. This is the right way to do it:

 string = "alabama%20justin"; console.log(decodeURIComponent(string)); 

Answer 2

Probably a more fancy way but simple check to see if it is a space followed by alpha or an alpha followed by a space

"12 july 2014 12 5".replace(/\s+([a-z])|([a-z])\s+/ig,'$1$2')

or

"12 july 2014 12 5".replace(/\s+([\D])|([\D])\s+/ig,'$1$2')