“未捕获到的SyntaxError：意外令牌：”
[英]'Uncaught SyntaxError: Unexpected token :'
问题描述
$(onReady); function onReady() { console.log('jq'); $('#submitButton').on('click', calcDistance); } function calcDistance() { console.log('button clicked'); $.ajax({ type:'GET', dataType: 'jsonp', contentType: "application/json", url:"https://www.zipcodeapi.com/rest/WvKkFrPlOUywte1GcfPJVGmhqHjTLwQH1B2H2R3QMCmfQoV2DLMzr8QRQ9KBGBiI/distance.json/55044/55124/mile/", header: { "Access-Control-Allow-Origin": "*" }, success: function(res) { console.log( 'back from ther server with',res ); }, error: function( err ){ console.log( err ); } }); }
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <!DOCTYPE html> <html> <head> <meta charset="utf-8"> <title></title> <script src="https://code.jquery.com/jquery-3.2.1.min.js" integrity="sha256-hwg4gsxgFZhOsEEamdOYGBf13FyQuiTwlAQgxVSNgt4=" crossorigin="anonymous"></script> <script src="client.js" charset="utf-8"></script> </head> <body> <h1>Zipcode</h1> <!-- <input id='firstZipcode' type="text" name="" value="First Zipcode"> <input id='secondZipcode' type="text" name="" value="Second Zipcode"> --> <button id='submitButton' type="button" name="button">Enter</button> </body> </html>
I am making a call to the zipcode api and i am getting the error "Uncaught SyntaxError: Unexpected token :". 
我正在对邮政编码api进行调用，并且收到错误"Uncaught SyntaxError: Unexpected token :". I have no idea where that is coming from. 我不知道那是哪里来的。 I am totally lost on how i would fix this. 我完全不知道如何解决这个问题。 Is it in the header when i make the ajax call? 我进行ajax调用时，它在标题中吗？ Do i need the content-type somewhere in there? 我是否需要在那里的内容类型？ The two zipcodes are hard coded into the url. 这两个邮政编码被硬编码到URL中。
1 个解决方案
解决方案1
0 已采纳 2017-07-05 18:04:08
In the first line you have ' $(onReady); 第一行中有' $(onReady); '. ”。 Try 尝试
jQuery(document).ready(function($){
..put all your other code here.
}
From what I can gather from your posted code it's the '$' that's not recognised, as it hasn't been bound to jQuery. 根据我从您发布的代码中收集到的信息，由于尚未绑定到jQuery，因此无法识别的是“ $”。
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