[英]I want to get bit of char on MPLAB XC8 but I can't?
My function to get bit is: 我得到的功能是:
extern volatile unsigned char Temp @ 0x036;
extern volatile __bit W @ (((unsigned) &Temp)*8) + 4;
void get_bit(volatile unsigned char *reg, unsigned num) {
W = (*reg & (1 << num));
}
Main function is: 主要功能是:
int main() {
volatile unsigned char ch = 0b00001000;
get_bit(&ch, 4);
}
When I compile this code of blocks I get an error (error: expression syntax). 当我编译这些代码块时,我得到一个错误(错误:表达式语法)。
What can I do to fix this problem? 我该怎么做才能解决此问题?
Try this code: 试试这个代码:
#include <stdio.h>
unsigned char get_bit(unsigned char reg, unsigned num)
{
return (reg & (1 << num));
}
unsigned char get_bit2(unsigned char reg, unsigned num)
{
return (reg & (1 << num))?1:0;
}
int main()
{
volatile unsigned char ch = 0b00001000;
ch |= (1<<4); // To set bit 4
printf("%d\n",get_bit(ch, 4)); // If you try on a PC
printf("%d\n",get_bit2(ch, 4)); // If you try on a PC
ch &= (~(1<<4)); // To reset bit 4
printf("%d\n",get_bit(ch, 4)); // If you try on a PC
printf("%d\n",get_bit2(ch, 4)); // If you try on a PC
return 0;
}
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