在C ++中的类成员函数中传递当前对象的引用

Question

Just like the this pointer is used to pass the pointer to the current object, how do I pass reference to the current object ?

class UseMe
{
    public:
         UseMe_funcReference(base&);
         UseMe_FuncPointer(base *)

}

class base{
..........
}
class Abc:public base
{
public:
   friend UseMe;
   UseMe innerObj;
   Func1()
   {
       (this->innerObj).UseMe_funcPointer(this); // This passes pointer to current object
       (this->innerObj).UseMe_funcReference(HOW_TO_PASS_REFERENCE_TO_CURRENT_OBJECT);
   }
}

Answer 1

You don't notate pass-by-reference that at the call site , there you use exactly the same syntax as a regular pass-by-value.

In the actual function, you use & to denote that the parameter is passed by reference. For example consider the function foo that takes a bar as a reference:

void foo(bar& reference);

Then you could use foo(*this) at the call site, if this is a bar* (or related) type.

Answer 2

您只需要使用*this ，就像从赋值运算符返回对self的引用时一样。

Answer 3

this is a pointer to the current object.

*this is a name for the current object.

Contrary to what some of the other people have said here, it is not a reference (dereferencing a T* gives you an lvalue T ), but you can bind a reference to it just as you would elsewhere.

tl;dr: dereference it, as you would any other pointer