[英]Restart my Python script
So I've created this number guessing game. 所以我创建了这个猜数字游戏。 And it works fine up until the play_again function is needed.
它可以正常工作,直到需要play_again函数。 I have looked around trying to figure out how I can restart the program.
我四处张望,试图弄清楚如何重新启动程序。 I have tested this in my PyCharm IDE and it just exits with exit code 0. What is the best way to actually restart the program so it generates a new number in my rand variable?
我已经在我的PyCharm IDE中对此进行了测试,它会以退出代码0退出。真正重启程序的最佳方法是什么,以便它在rand变量中生成一个新数字?
import os
from random import random
import sys
class Game:
"""
rand is declared by grabbing a number between 0 and 1, multiplying it by 100, and rounding to the nearest integer
guessed is declared as false in order to keep the while loop running until the number is guessed
"""
rand = round(random() * 100, 0)
guessed = False
print("Guess the number [0 - 100]")
# This function handles the number guessing and number formatting
def run_game(self):
# Assigns the 'answer' variable by grabbing user input from console
answer = input()
# Checks if the input from the console is a number, and if not, asks the user to enter a valid number
if answer.isdigit():
n = int(answer)
# Checks the input given against the random number generated
while not self.guessed:
if n > int(self.rand):
print("Number is less than " + str(n))
self.run_game()
elif n < int(self.rand):
print("Number is greater than " + str(n))
self.run_game()
else:
print("You have guessed the correct number!")
self.guessed = True
self.play_again()
else:
print("Please enter a number")
self.run_game()
return
def play_again(self):
reply = input("Play again? (y/n)")
if reply.lower() == "y":
python = sys.executable
os.execl(python, python, *sys.argv)
elif reply.lower() == "n":
print("Thanks for playing!")
else:
self.play_again()
if __name__ == "__main__":
game = Game()
game.run_game()
There are several errors in your code. 您的代码中有几个错误。 The most common being is that you are using recursion as a looping construct.
最常见的是您将递归用作循环构造。 Don't do this.
不要这样 It's a great way to introduce bugs, not to mention if your "loop" runs to many times, you'll hit the recursion limit.
这是引入错误的好方法,更不用说如果您的“循环”运行了很多次,您将达到递归限制。 Just use a
while
loop: 只需使用
while
循环:
def run_game(self):
while True:
answer = input()
if answer.isdigit():
n = int(answer)
if n > int(self.rand):
print("Number is less than " + str(n))
elif n < int(self.rand):
print("Number is greater than " + str(n))
else:
print("You have guessed the correct number!")
reply = self.play_again()
if reply is False:
break
else:
print("Please enter a number")
Note a modified player to return a boolean indicating whether the user wants to play again. 请注意,修改后的播放器将返回一个布尔值,该布尔值指示用户是否要再次播放。 As I said above, you made the same mistake in player.
如上所述,您在播放器中犯了同样的错误。 Don't use a recursion as a loop, use an explicit while loop:
不要将递归用作循环,而应使用显式的while循环:
def play_again(self):
while True:
reply = input("Play again? (y/n)")
if reply.lower() == "y":
return True
elif reply.lower() == "n":
return False
else:
print("Enter 'y' or 'n'")
On an unrelated side note, I see no reason to use a class here. 另外,我没有理由在这里使用类。 There's no global state you need to keep track of or any data you're trying to encapsulate.
您无需跟踪任何全局状态,也无需尝试封装任何数据。 This can be implemented much cleaner using just functions:
仅使用函数就可以实现更简洁的实现:
def run_game():
rand = randint(1, 100)
while True:
answer = input()
if answer.isdigit():
n = int(answer)
if n > rand:
print("Number is less than " + str(n))
elif n < rand:
print("Number is greater than " + str(n))
else:
print("You have guessed the correct number!")
if not play_again():
break
else:
print("Please enter a number")
def play_again():
while True:
reply = input("Play again? (y/n)")
if reply.lower() == "y":
return True
elif reply.lower() == "n":
return False
else:
print("Enter 'y' or 'n'")
if __name__ == "__main__":
print("Guess the number [0 - 100]")
run_game()
Here are some other improvements I made: 这是我所做的其他一些改进:
ranint()
instead of randomm()
. ranint()
代替randomm()
。 Since you have a specific range, just use randint()
. randint()
。 int()
as those are no longer needed. int()
的调用,因为不再需要这些调用。 That's a pretty bad way to restart the game, you should avoid running exec
when possible. 这是重启游戏的一种非常糟糕的方法,您应尽可能避免执行
exec
。
One other way to do it would be to return False
or True
based on user input, and keep running the game while the function returns True
: 另一种方法是根据用户输入返回
False
或True
,并在函数返回True
继续运行游戏:
import os
from random import random
import sys
class Game:
"""
rand is declared by grabbing a number between 0 and 1, multiplying it by 100, and rounding to the nearest integer
guessed is declared as false in order to keep the while loop running until the number is guessed
"""
rand = round(random() * 100, 0)
guessed = False
print("Guess the number [0 - 100]")
# This function handles the number guessing and number formatting
def run_game(self):
# Assigns the 'answer' variable by grabbing user input from console
answer = input()
# Checks if the input from the console is a number, and if not, asks the user to enter a valid number
if answer.isdigit():
n = int(answer)
# Checks the input given against the random number generated
while not self.guessed:
if n > int(self.rand):
print("Number is less than " + str(n))
self.run_game()
elif n < int(self.rand):
print("Number is greater than " + str(n))
self.run_game()
else:
print("You have guessed the correct number!")
self.guessed = True
return self.play_again() # Here we run play_again and return its result
else:
print("Please enter a number")
self.run_game()
return
def play_again(self):
reply = input("Play again? (y/n)")
if reply.lower() == "y":
return False # Game isn't finished
elif reply.lower() == "n":
print("Thanks for playing!")
return False # Game is finished
else:
return self.play_again()
if __name__ == "__main__":
game = Game()
game_is_finished = False
while not game_is_finished:
game_is_finished = game.run_game()
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