在Python中查找列表中任何项的最连续序列

Question

How can I find the most consecutive sequence of any item(integers) of a list in Python?

my_list = [1, 3, 2, 2, 4, 5, 5, 5, 5, 6, 1, 5, 5]

I want to extract [5, 5, 5, 5] from the list.

NB Please, correct me if I've written anything wrong. :-)

Answer 1

Use itertools.groupby() and max() :

In [1]: my_list = [1, 3, 2, 2, 4, 5, 5, 5, 5, 6, 1, 5, 5]

In [2]: from itertools import groupby

In [4]: max([list(g) for _, g in groupby(my_list)], key=len)
Out[4]: [5, 5, 5, 5]