如何在单行中获取数据 <td> ，具有相同ID的数据库中的多个条目

Question

table structure is like as:

medicine table                    component table
id | name                        id | medicine_id | component_name
----------------                -----------------------------------
1  |  a                           1 |      1      |       aaaa
2  |  b                           2 |      1      |       bbbb   
3  |  b                           3 |      1      |       cccc
                                  4 |      2      |       abab
                                  5 |      2      |       baba
                                  6 |      3      |       zzzz

My query is

$query = "SELECT med_name, component_name FROM medicine left JOIN component ON medicine.id=component.medicine_id order by medicine.med_name";

PHP Code

$result = $mysqli -> query($query);

while ($row = $result -> fetch_array()) {

echo '<tr><td>' . $row['med_name'] . '</td><td>' . $row['component_name'] . '</td><td>' . $row['component_name'] . '</td><td>' . $row['component_name'] . '</td><td>' . $row['component_name'] . '</td><td><a href="edit.php?id=' . $row['id'] . '"><i class="fa fa-edit text-success text-active"></i> Edit</a></td></tr>';

}

with this code my html output is like:

medicine | component1 | component2 | component3 | component4
-------------------------------------------------------------
  a      |    aaaa    |    aaaa    |    aaaa    |    aaaa
  a      |    bbbb    |    bbbb    |    bbbb    |    bbbb
  a      |    cccc    |    cccc    |    cccc    |    cccc
  b      |    abab    |    abab    |    abab    |    abab
  b      |    baba    |    baba    |    baba    |    baba
  c      |    zzzz    |    zzzz    |    zzzz    |    zzzz

but I want html output as:

 medicine | component1 | component2 | component3 | component4
--------------------------------------------------------------
    a     |    aaaa    |    bbbb    |    cccc    |
    b     |    abab    |    baba    |            |
    c     |    zzzz    |            |            |

Answer 1

What you're trying to do is just a bit more complicated that what you're doing. Your query seems fine. But after you fetch the results there's a little more work to do to determine how the table should be produced. I would start by fetching the rows into a multidimensional array, where multiple component rows are stored under each medicine name, like this:

while ($row = $result->fetch_array()) {
    $medicines[$row['med_name']][] = $row;
}

Then you'll need to find the maximum number of components for any of the medicines you fetched, so you can know how many columns your table should have.

$component_columns = max(array_map('count', $medicines));

Then you can iterate your array of medicines and output each one as a row with its components as additional columns.

foreach ($medicines as $medicine => $components) {

    // start the row and echo the medicine name
    echo "<tr><td>$medicine</td>";

    // echo the components, keeping track of how many you've done so far
    $i = 0;
    foreach ($components as $component) {
        echo "<td>$component[component_name]</td>";
        $i++;
    }

    // then echo empty cells to fill the rest of the row
    for (; $i < $component_columns; $i++) {
        echo "<td>&nbsp;</td>";
    }
    echo '<tr>';

}

By the way, it looks like you're using the medicine id in a link in your HTML, but if you want to add that, you'll need to be sure to include that in the selected columns in your query as well.

Answer 2

when i apply this pagination it break any random single row to double row. And its pagination is like"1|2|3|4|5|6|so on" not like "1|2|3|4|5|last" or "First|4|5|6|last".

   function generate_page_links($cur_page, $num_pages) {
                    $page_links = '';

                    // If this page is not the first page, generate the "previous" link
                    if ($cur_page > 1) {
                        $page_links .= '<li><a href="' . $_SERVER['PHP_SELF'] . '?page=' . ($cur_page - 1) . '">&laquo;</a></li> ';
                    } else {
                        $page_links .= '<li  class="disabled"><a href="#" >&laquo; </a></li>';
                    }

                    // Loop through the pages generating the page number links
                    for ($i = 1; $i <= $num_pages; $i++) {
                        if ($cur_page == $i) {
                            $page_links .= '  <li class="active"><a href="#" >' . $i . '</a></li>';
                        } else {
                            $page_links .= ' <li><a href="' . $_SERVER['PHP_SELF'] . '?page=' . $i . '"> ' . $i . '</a></li>';
                        }
                    }

                    // If this page is not the last page, generate the "next" link
                    if ($cur_page < $num_pages) {
                        $page_links .= ' <li><a href="' . $_SERVER['PHP_SELF'] . '?page=' . ($cur_page + 1) . '">&raquo;</a></li>';
                    } else {
                        $page_links .= '<li  class="disabled"><a href="#" >&raquo;</a></li>';
                    }

                    return $page_links;
                }