如何链接路由（使用`~`）是函数的结果？

Question

scala> import akka.http.scaladsl.server._; import Directives._
import akka.http.scaladsl.server._
import Directives._

Suppose I have two functions from some type ( Int , say) to a Route :

scala> lazy val r1: Int => Route = ???
r1: Int => akka.http.scaladsl.server.Route = <lazy>

scala> lazy val r2: Int => Route = ???
r2: Int => akka.http.scaladsl.server.Route = <lazy>

I can compose a route thusly:

scala> lazy val composite: Route = path("foo"){ r1(1) } ~ path("bar"){ r2(1) }
composite: akka.http.scaladsl.server.Route = <lazy>

What I would like to do is use function composition together with the ~ path chaining. That is, I'd love for this to just work:

scala> lazy val composite: Int => Route = path("foo")(r1) ~ path("bar")(r2)

Except it doesn't :-(

<console>:31: error: type mismatch;
 found   : Int => akka.http.scaladsl.server.Route
    (which expands to)  Int => (akka.http.scaladsl.server.RequestContext => scala.concurrent.Future[akka.http.scaladsl.server.RouteResult])
 required: akka.http.scaladsl.server.Route
    (which expands to)  akka.http.scaladsl.server.RequestContext => scala.concurrent.Future[akka.http.scaladsl.server.RouteResult]
       lazy val composite: Int => Route = path("foo")(r1) ~ path("bar")(r2)
                                                      ^

EDIT

I am trying to do this using point-free function composition,. As Ramon 's answer below demonstrates, it's easy to do this if you are willing to duplicate the function application (but this is what I want to avoid). That is:

lazy val composite: Int => Route 
  = i => path("foo")(r1(i)) ~ path("bar")(r2(i))

NOTE

Using scalaz , I can do this:

scala> import akka.http.scaladsl.server._; import Directives._; import scalaz.syntax.monad._; import scalaz.std.function._
import akka.http.scaladsl.server._
import Directives._
import scalaz.syntax.monad._
import scalaz.std.function._

scala> lazy val r1: Int => Route = ???
r1: Int => akka.http.scaladsl.server.Route = <lazy>

scala> lazy val r2: Int => Route = ???
r2: Int => akka.http.scaladsl.server.Route = <lazy>

scala> lazy val composite = for (x <- r1; y <- r2) yield path("foo")(x) ~ path("bar")(y)
composite: Int => akka.http.scaladsl.server.Route = <lazy>

Which is so good as it goes but the implicit ConjunctionMagnet.fromRouteGenerator in akka.http.scaladsl.server gives me cause to think it might be possible in akka-http directly

Answer 1

The equivalent to the scalaz example you gave is:

lazy val composite: Int => Route = 
  (i) => path("foo")(r1(i)) ~ path("bar")(r2(i))

Similarly, you could anonymize the parameter name but that would result in 2 parameters:

lazy val composite: (Int,Int) => Route = path("foo")(r1(_)) ~ path("bar")(r2(_))