Java contains（）方法无法正常工作

Question

I'm writing small condition to check if certain character are exist or not in java. This is my string: May i know how much I spent on food?

I'm checking if food string is exist or not, if i check "food" in if condition I'm getting proper response, if i use "Food" or "fOod" or "fOOd" or "fooD" its always going to else block. What I'm doing wrong here:

String food = "may i know how much I spent on food";

if(food.contains("Food")) {
    System.out.println("Food Expense is 32");

} else {
    System.out.println("Not Matching");
}

Answer 1

That is because the difference in cases. "Food".equals("food") will give you false. To solve the problem of cases you can convert everything to lower when searching

if (food.toLowerCase().contains("Food".toLowerCase())) {}

And you can have any variation of food in the if condition. No need to worry about case sensitivity with this

Answer 2

Try this

if(food.toLowerCase().contains("Food".toLowerCase())) {
System.out.println("Food Expense is 32");

} else {
System.out.println("Not Matching");
}