在Python中合并文件

Question

I want to merge 2 files. First file ( co60.txt ) contains only integer values and the second file ( bins.txt ) contains float numbers.

co60.txt:

11
14
12
14
18
15
18
9

bins.txt:

0.00017777777777777795
0.0003555555555555559
0.0005333333333333338
0.0007111111111111118
0.0008888888888888898
0.0010666666666666676
0.0012444444444444456
0.0014222222222222236

When I merge those two file with this code:

with open("co60.txt", 'r') as a:
    a1 = [re.findall(r"[\w']+", line) for line in a]
with open("bins.txt", 'r') as b:
    b1 = [re.findall(r"[\w']+", line) for line in b]
with open("spectrum.txt", 'w') as c:
    for x,y in zip(a1,b1):
        c.write("{} {}\n".format(" ".join(x),y[0]))

I get:

11 0
14 0
12 0
14 0
18 0
15 0
18 0
9 0

It appears that when I merge these 2 files, this code only merges round values of the file bins.txt .

How do I get that files merge like this:

11 0.00017777777777777795
14 0.0003555555555555559
12 0.0005333333333333338
14 0.0007111111111111118
18 0.0008888888888888898
15 0.0010666666666666676
18 0.0012444444444444456
9 0.0014222222222222236

Answer 1

You can do it without regex::

with open("co60.txt") as a, open("bins.txt") as b, \
    open("spectrum.txt", 'w') as c:
    for x,y in zip(a, b):
        c.write("{} {}\n".format(x.strip(), y.strip()))

Content of spectrum.txt :

11 0.00017777777777777795
14 0.0003555555555555559
12 0.0005333333333333338
14 0.0007111111111111118
18 0.0008888888888888898
15 0.0010666666666666676
18 0.0012444444444444456
9 0.0014222222222222236

Answer 2

如@immortal所述，如果要使用正则表达式，请使用-

b1 = [re.findall(r"[0-9\.]+", line) for line in b]