glob.glob结果不一致

Question

Can anyone tell me why this command works:

lefs = glob.glob(".\lef\*.lef")

but this doesnt?

techFiles = glob.glob(".\techfile\*.tcl")

I have to add the extra backslash in order for it to work:

techFiles = glob.glob(".\\techfile\*.tcl")

The other line works fine with no extra backslash.. These are just simple files with different extensions.

All files exists and are in the correct directory.

Answer 1

in techFiles = glob.glob(".\\techfile\\*.tcl") , \\t is interpreted as a tabulation char (other "problematic chars are \\b , \\v , \\a , \\x , \\b , \\f , \\U , \\ followed by a digit, ... I may forget some)

So the path is invalid and glob.glob returns nothing.

Your other path contains \\l and \\* which doesn't correspond to any escape sequence, so it is not interpreted and kind of works.

To pass string literals as Windows paths, always use raw prefix, it's simpler than escaping each backslash:

techFiles = glob.glob(r".\techfile\*.tcl")

Slightly off-topic: there's a lot of code examples here with capitalized directory names: ex glob.glob(".\\Techfile\\Backlog\\*.tcl") , and I always wondered if it was mere luck, or if most people still don't get this \\t issue and find a workaround by capitalizing, since Windows paths are case-insensitive...