sed，在模式匹配后插入一行，并忽略任何以＃开头的注释行

Question

I would like to insert a line after a pattern match and ignore any commented line ( starting with '#' ) in Bash shell using sed .

Here is an example: inserting a new line after pattern :

Input file:

foo
Art 
street 
#pattern
foo
pattern
color

Output:

foo
Art 
street 
#pattern
foo
pattern
NEW LINE HERE
color

Answer 1

With sed :

$ cat file
foo
Art
street
#pattern
foo
pattern
color

$ sed '/^[^#]*pattern/ a NEW LINE HERE' file
foo
Art
street
#pattern
foo
pattern
NEW LINE HERE
color

Answer 2

尝试跟随一次。

awk '/pattern/ && !/#/{print $0 ORS "NEW LINE HERE";next} 1'   Input_file

Answer 3

Another approach with sed:

sed 's/^pattern.*/&\nNEW LINE HERE/' file

Replace line starting with pattern with matching line( & ) followed by new line( \\n ) and desired string.

Answer 4

Using awk :

awk -v line='NEW LINE HERE' -v pat='pattern' '1; $0 ~ pat && !/^[ \t]*#/{print line}' file

foo
Art
street
#pattern
foo
pattern
NEW LINE HERE
color