Python日期转换为EPOCH

Question

import time
print(int(time.mktime(time.strptime('2017-08-12T17:07:46', '%Y-%m-%dT%H:%M:%S'))))

I get 1502582866 and I expect 1502557666? Any help is welcome

Answer 1

Yes, @Paul is correct: according to the documentation, mktime will take a struct_time in local time and convert it to seconds since the epoch , which has no timezones nor daylight savings.

So, your initial time of:

`2017-08-12T17:07:46`

becomes:

1502582866 ==> `GMT: Sunday, August 13, 2017 12:07:46 AM`

which is correct.

If you are wondering how to correctly convert back, you would use localtime :

import time
epoch_time = 1502582866
time_string = time.strftime('%Y-%m-%dT%H:%M:%S', time.localtime(epoch_time))
print time_string
>> 2017-08-12T17:07:46

Also see a sample in action here: https://eval.in/845075