在Java 7中使用正则表达式使用换行符查找模式

Question

I am writing a regular expression being used to search through files and find the following pattern:

{@link ClassName} provides
 *

I have written this expression so far using java.util.regex.Pattern :

private static final Pattern MY_PATTERN =
        Pattern.compile("\\{@link [a-zA-Z0-9]*\\} provides\r\n \\*");

However, this is not finding any matches. I have got as far as finding the pattern without the newline, but trying to search for the pattern with the newline and '*' character is proving difficult.

How else can I check if there is a newline followed by a '*'? I've also tried '\\r' and '\\n' on their own in the pattern.

Note: I'm using Java version 1.7.0_25

Update Showing my code (left out the bit where I print out the matches to console):

public class PatternSearcher
{
    private static final String JAVA_FILES_GLOB = "glob:**/*.java";
    private static final Pattern MY_PATTERN =
        Pattern.compile("\\{@link [a-zA-Z0-9]*\\} provides\r\n \\*");

    @Test
    public void checkForPattern() throws Exception
    {
        final StringBuilder filesWithPattern = new StringBuilder();

        final PathMatcher pathMatcher = FileSystems.getDefault().getPathMatcher(JAVA_FILES_GLOB);

        Files.walkFileTree(SourceCodeTestUtil.getErsCoreDir().toPath(), new SimpleFileVisitor<Path>()
        {
            @Override
            public FileVisitResult visitFile(final Path file, final BasicFileAttributes attrs) throws IOException
            {
                if (pathMatcher.matches(file))
                {
                    for (final String line : Files.readAllLines(file, Charset.defaultCharset()))
                    {
                        if (MY_PATTERN.matcher(line).find())
                        {
                            filesWithPattern.append(file).append("\n");
                        }
                    }
                }
                return FileVisitResult.CONTINUE;
            }
        });
    }
}

Answer 1

您可以尝试以下模式

"\\{@link \\w+\\} provides\\n \\*"

Answer 2

It works with this:

private static final Pattern MY_PATTERN =
        Pattern.compile("\\{@link [a-zA-Z0-9]*\\} provides(\\r|\\n|\\r\\n) \\*");