[英]Create a new Column of previous N rows as an Array
I have a dataframe df that looks like this, 我有一个看起来像这样的数据框df,
a b
0 30.05 29.55
1 30.20 26.05
2 30.81 25.65
3 31.12 26.44
.. ... ...
85 30.84 25.65
86 31.12 26.44
87 29.55 25.57
88 32.41 25.45
89 21.55 29.57
90 32.91 26.41
91 34.12 25.69
I need to create a new Column 'c' that holds an Array of Column 'b' value plus the previous 4 rows values of Column 'b'. 我需要创建一个新列'c',其中包含列'b'值的数组加上列'b'的前4行值。 So the resulting df would look like, 因此产生的df看起来像
a b c
0 30.05 29.55 [29.55,0,0,0,0]
1 30.20 26.05 [26.05,29.55,0,0,0]
2 30.81 25.65 [25.65,26.05,29.55,0,0]
3 31.12 26.44 [26.44,25.65,26.05,29.55,0]
.. ... ...
85 30.84 25.65 [25.65, 44.60, 30.15, 29.55, 24.66 ]
86 31.12 26.44 [26.44, 25.65, 25.65, 25.65, 25.65 ]
87 29.55 25.57 [25.57, 26.44, 25.65, 25.65, 25.65 ]
88 32.41 25.45 [25.45, 25.57, 26.44, 25.65, 25.65 ]
89 21.55 29.57 [29.57, 25.45, 25.57, 26.44, 25.65 ]
90 32.91 26.41 [26.41, 29.57, 25.45, 25.57, 26.44 ]
91 34.12 25.69 [25.69, 26.41, 29.57, 25.45, 25.57 ]
I know I can access previous rows with df.b.shift(1) and df.b.shift(2) etc but I want to be able to easily change how many rows I look back to form the array with a variable rather than type out the many shift(n) 我知道我可以使用df.b.shift(1)和df.b.shift(2)等访问以前的行,但是我希望能够轻松更改我回头看的行数,以形成一个变量而不是数组输入多班次(n)
After looking all day I'm stuck. 看了一整天后,我被困住了。 (python3.6) (python3.6)
You could use pd.concat
with range(N)
您可以将pd.concat
与range(N)
In [60]: df['c'] = pd.concat([df.b.shift(i) for i in range(4)], 1).fillna(0).values.tolist()
In [61]: df
Out[61]:
a b c
0 30.05 29.55 [29.55, 0.0, 0.0, 0.0]
1 30.20 26.05 [26.05, 29.55, 0.0, 0.0]
2 30.81 25.65 [25.65, 26.05, 29.55, 0.0]
3 31.12 26.44 [26.44, 25.65, 26.05, 29.55]
85 30.84 25.65 [25.65, 26.44, 25.65, 26.05]
86 31.12 26.44 [26.44, 25.65, 26.44, 25.65]
87 29.55 25.57 [25.57, 26.44, 25.65, 26.44]
88 32.41 25.45 [25.45, 25.57, 26.44, 25.65]
89 21.55 29.57 [29.57, 25.45, 25.57, 26.44]
90 32.91 26.41 [26.41, 29.57, 25.45, 25.57]
91 34.12 25.69 [25.69, 26.41, 29.57, 25.45]
Or , use np.column_stack
on shift(n)
或者 ,在shift(n)
上使用np.column_stack
In [70]: np.column_stack([df.b.shift(i).fillna(0) for i in range(4)]).tolist()
Out[70]:
[[29.55, 0.0, 0.0, 0.0],
[26.05, 29.55, 0.0, 0.0],
[25.65, 26.05, 29.55, 0.0],
[26.44, 25.65, 26.05, 29.55],
[25.65, 26.44, 25.65, 26.05],
[26.44, 25.65, 26.44, 25.65],
[25.57, 26.44, 25.65, 26.44],
[25.45, 25.57, 26.44, 25.65],
[29.57, 25.45, 25.57, 26.44],
[26.41, 29.57, 25.45, 25.57],
[25.69, 26.41, 29.57, 25.45]]
You can use a conditional list comprehension (to check when the lookback is before the first value in the index). 您可以使用条件列表推导(检查回溯何时在索引中的第一个值之前)。
rows_lookback = 5
df = df.assign(c=[[df['b'].iat[n - i] if n - i >= 0 else 0
for i in range(rows_lookback)]
for n in range(len(df['b']))])
>>> df
a b c
0 30.05 29.55 [29.55, 0, 0, 0, 0]
1 30.20 26.05 [26.05, 29.55, 0, 0, 0]
2 30.81 25.65 [25.65, 26.05, 29.55, 0, 0]
3 31.12 26.44 [26.44, 25.65, 26.05, 29.55, 0]
85 30.84 25.65 [25.65, 26.44, 25.65, 26.05, 29.55]
86 31.12 26.44 [26.44, 25.65, 26.44, 25.65, 26.05]
87 29.55 25.57 [25.57, 26.44, 25.65, 26.44, 25.65]
88 32.41 25.45 [25.45, 25.57, 26.44, 25.65, 26.44]
89 21.55 29.57 [29.57, 25.45, 25.57, 26.44, 25.65]
90 32.91 26.41 [26.41, 29.57, 25.45, 25.57, 26.44]
91 34.12 25.69 [25.69, 26.41, 29.57, 25.45, 25.57]
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