[英]jQuery - replace attribute value with new value of all elements
I've this html markup: 我有这个html标记:
<div class="item" path="asaa/basba/asbsaa"></div>
<div class="item" path="bsbab/gbfssv/vsaava"></div>
<div class="item" path="asbaba/bsaba/dfsavava"></div>
The important point is that each is different. 重要的是,每个都是不同的。 I need to get this attributes with something like that that: 我需要用类似这样的属性:
var title = $(this).attr('path'); var title = $(this).attr('path');
Now I need to separate the attribute: I need only the content which is between the * and the *: 现在,我需要分离属性:我只需要*和*之间的内容:
<div class="item" path="asaa/basba/*asbsaa*"></div>
<div class="item" path="bsbab/gbfssv/*vsaava*"></div>
<div class="item" path="asbaba/bsaba/*dfsavava*"></div>
Any ideas to do something like that? 有类似的想法吗? Thanks for answers! 感谢您的回答!
Get the attribute of each element and then setting back the last part of it 获取每个元素的属性,然后返回其最后一部分
$(".item").attr("path",function(){ return $(this).attr("path").split("/").pop(); }) console.log($('body').html());
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <div class="item" path="asaa/basba/asbsaa"></div> <div class="item" path="bsbab/gbfssv/vsaava"></div> <div class="item" path="asbaba/bsaba/dfsavava"></div>
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