Spring RestTemplate处理自定义状态代码

Question

I should call some service from my application that can return unusual http status codes, such as 230, 240 etc. By default error handler I'm getting:

Servlet.service() for servlet [dispatcher] in context with path [] threw exception [Request processing failed; nested exception is org.springframework.web.client.UnknownHttpStatusCodeException: Unknown status code [230] null] with root cause...

When I use my custom error handler I can avoid this:

@Override
    public boolean hasError(ClientHttpResponse response) throws IOException {

        int status = response.getRawStatusCode();
        if (status >= 200 && status <= 299)
            return false;

        HttpStatus statusCode = response.getStatusCode();
        if (statusCode.is2xxSuccessful())
            return false;
        HttpStatus.Series series = statusCode.series();
        return (HttpStatus.Series.CLIENT_ERROR.equals(series)
                || HttpStatus.Series.SERVER_ERROR.equals(series));
    }

But when RestTmplate tries to retrieve it falls into the same exception in MessageBodyClientHttpResponseWrapper :

public boolean hasMessageBody() throws IOException {
        HttpStatus responseStatus = this.getStatusCode();
        if (responseStatus.is1xxInformational() || responseStatus == HttpStatus.NO_CONTENT ||
                responseStatus == HttpStatus.NOT_MODIFIED) {
            return false;
        }
        else if (this.getHeaders().getContentLength() == 0) {
            return false;
        }
        return true;
    }

How can I get response body correctly?

Answer 1

最后，在Spring 5解决了问题， 对其进行了测试 。