D3 v4 - 获取轴上每个刻度的值？
[英]D3 v4 - Get the value of the each tick present on an axis?
问题描述
Using D3.js version 4, is there a way to get an array of the values for each tick on an axis?
使用 D3.js 版本 4，有没有办法获取轴上每个刻度的值数组？
Edit:编辑：
From D3 documentation来自 D3文档
# axis.tickValues([values]) <>
If a values array is specified, the specified values are used for ticks rather than using the scale's automatic tick generator.
I am using the automatic tick generator so if I call我正在使用自动滴答生成器，所以如果我打电话
var tickValues = axis.tickValues();
tickValues is null tickValues值为null
2 个解决方案
解决方案1
11 已采纳 2017-09-01 19:11:18
If you have a reference to the axis , you can use:如果您有对轴的引用，则可以使用：
axis.scale().ticks()
If you want them all formatted out, I'd get them from the DOM:如果你想让它们全部格式化，我会从 DOM 中获取它们：
d3.selectAll(".tick>text")
.nodes()
.map(function(t){
return t.innerHTML;
})
Running code:运行代码：
<!DOCTYPE html> <meta charset="utf-8"> <svg width="960" height="500"></svg> <script src="//d3js.org/d3.v4.min.js"></script> <script> var svg = d3.select("svg"), margin = {top: 20, right: 0, bottom: 20, left: 0}, width = svg.attr("width") - margin.left - margin.right, height = svg.attr("height") - margin.top - margin.bottom, g = svg.append("g").attr("transform", "translate(" + margin.left + "," + margin.top + ")"); var x = d3.scalePoint() .domain([0, 1, 2]) .range([0, width]) .padding(1); var y = d3.scaleLinear() .domain([-1e6, 2e6]) .range([height, 0]); var axis = d3.axisLeft(y) .ticks(20, "s"); g.append("g") .attr("transform", "translate(" + x(0) + ",0)") .attr("class", "axis") .call(axis); console.log( axis.scale().ticks() ); console.log( d3.selectAll(".tick>text") .nodes() .map(function(t){ return t.innerHTML ; }) ); </script>
解决方案2
0 2020-09-21 09:37:27
I found the answer of Mark above was not correct for my case, I changed a bit from his inspiration and it worked我发现上面马克的答案不适合我的情况，我从他的灵感中改变了一点，它奏效了
// I am using d3-scale
const yScale = scaleLinear().domain(realYDomain).range([30, 170]);
// I am using d3-axis
const yAxis = axisLeft(yScale); // Not declare axisLeft(scale).ticks(number) here, but below line instead
const tickValues = yAxis.scale().ticks(5);
console.log(tickValues);
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