[英]Laravel 500 error, Base64 images, Ajax and array's
I am uploading, or better said, trying to upload images to my Laravel website with Ajax. 我正在上传,或者更好地说, 尝试使用Ajax将图像上传到我的Laravel网站。 I convert the images to Base64 and upload them to the server.
我将图像转换为Base64并将它们上传到服务器。 It works, sort of.
它有效。
My problem is that I get a 500 error. 我的问题是我得到500错误。
It's the response from the server in an Iframe 这是来自iframe服务器的响应
The thing is, I do not get this error all the times. 问题是,我不会一直得到这个错误。 I only get it when I try to do something with the response.
当我尝试对响应做些什么时,我才会得到它。
This is my method where I handle the upload. 这是我处理上传的方法。 When I run it like this everything works and I do not get the error.
当我像这样运行它一切正常,我没有得到错误。
public function upload(Request $request)
{
return var_dump($request->all());
}
But it is an array. 但它是一个阵列。 So to do something with it I have to specify the key.
所以要用它做点什么我必须指定键。 Only problem is that as soon I do that I get the 500 error.
唯一的问题是,一旦我这样做,我得到500错误。
I want to convert the base64 string back to an image so I want to do this: 我想将base64字符串转换回图像,所以我想这样做:
file_put_contents('foo.png', base64_decode($request->all()[0]));
But this creates the error. 但这会产生错误。 the
[0]
at the end of $request->all()
. $request->all()
结束时的[0]
。
I can't remove it because it needs a base64 string and not an array. 我无法删除它,因为它需要base64字符串而不是数组。 I also wanted to know what would happen if I just add
[0]
to the end of $request-all()
in the var dump but I still got the errror. 我还想知道如果我在var转储中将
[0]
添加到$request-all()
的末尾会发生什么,但我仍然得到错误。
I just don't get it. 我只是不明白。
This is my Ajax call: 这是我的Ajax调用:
$.ajax({
url: "/admin/upload",
type: "POST",
data: queue,
processData: false,
error: function(xhr, status, error) {
let err = xhr.responseText;
//console.log(err);
$('#upload-InnerPanel').append("<iframe width='600' height='500' src='" + err +"'> </iframe>")
},
success: function (xhr) {
console.log(xhr);
},
headers: {
'X-CSRF-TOKEN': $('meta[name="csrf-token"]').attr('content')
}
});
Answered in the comments, but posting this as an answer anyway: 在评论中回答,但无论如何都将此作为答案发布:
The $request value that is received isn't numerically indexed, so you need to access it using its name. 收到的$ request值未按数字索引,因此您需要使用其名称访问它。 Instead of
$request->all()[0]
, you would need to use $request->theData
, or whatever the value is named in the form. 而不是
$request->all()[0]
,你需要使用$request->theData
,或者在表单中命名的值。
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.