正则表达式提取引号之间的数据

Question

As title says string is '="24digit number"' and I want to extract number between "" (example: ="000021484123647598423458" should get me '000021484123647598423458' ).

There are answers that answer how to get data between " but in my case I also need to confirm that =" exist without capturing (there are also other "\\d{24}" strings, but they are for other stuff) it.

I couldn't modify these answers to get what I need.

My latest regex was ((?<=\\")\\d{24}(?=\\")) and string is ="000021484123647598423458" .

UPDATE: I think I will settle with pattern r'^(?:\\=\\")(\\d{24})(?:\\")' because I just want to capture digit characters.

word = '="000021484123647598423458"' pattern = r'^(?:\\=\\")(\\d{24})(?:\\")' match = re.findall(pattern, word)[0]

Thank you all for suggestions.

Answer 1

You could have it like:

=(['"])(\d{24})\1

See a demo on regex101.com .

---

In Python :

 import re string = '="000021484123647598423458"' rx = re.compile(r'''=(['"])(\\d{24})\\1''') print(rx.search(string).group(2)) # 000021484123647598423458 

Answer 2

Any one of the following works:

>>> st = '="000021484123647598423458"'
>>> import re 
>>> re.findall(r'".*\d+.*"',st)
['"000021484123647598423458"']

or

>>> re.findall(r'".*\d{24}.*"',st)
['"000021484123647598423458"']

or

>>> re.findall(r'"\d{24}"',st)
['"000021484123647598423458"']