[英]extract phrase between single quotes regex and python
I want to extract from text phrases which are usually between single quotation我想从通常在单引号之间的文本短语中提取
def extract_phrase(s):
list = []
pattern = re.compile("(?<=')[^']+(?=')")
for value in pattern.findall(s):
list.append(value)
return list
print(extract_phrase("I can't Sleep and 'black lives matter'"))
['t Sleep and ', 'black lives matter']
as you can see the code return 2 strings, which is not good because I want only the 'black lives matter' to return.如您所见,代码返回 2 个字符串,这并不好,因为我只想返回“黑人的命也是命”。
to fix it I tried to put \\b at the start and in the end of the regex expression but i did not recieve anything when i made that change.为了解决这个问题,我尝试将 \\b 放在正则表达式的开头和结尾,但是当我进行更改时我没有收到任何信息。
so how can i change the regex statement so i will get all strings from text that start with ' and end with '.那么如何更改正则表达式语句,以便从文本中获取所有以 ' 开头并以 ' 结尾的字符串。
thank you谢谢你
If your single quotes are all balanced and unescaped then you may use this regex:如果您的单引号都是平衡且未转义的,那么您可以使用此正则表达式:
\B'.*?'(?!\w)
RegEx Details:正则表达式详情:
\\B
: Asserts position where \\b
does not match \\B
:断言\\b
不匹配的位置'
matches the character '
'
匹配字符'
.*?
: Matches 0 or more of any character (?!\\w)
: Negative lookahead to assert that next character is not a word character (?!\\w)
:否定前瞻断言下一个字符不是单词字符
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