[英]Using a borrow as an associated trait type
This code works: 此代码有效:
struct Test {
val: String,
}
impl Test {
fn mut_out(&mut self) -> &String {
self.val = String::from("something");
&self.val
}
}
However, a more generic implementation does not work: 但是,更通用的实现不起作用:
struct Test {
val: String,
}
trait MutateOut {
type Out;
fn mut_out(&mut self) -> Self::Out;
}
impl MutateOut for Test {
type Out = &String;
fn mut_out(&mut self) -> Self::Out {
self.val = String::from("something");
&self.val
}
}
The compiler cannot infer a lifetime for the string borrow: 编译器无法推断字符串借用的生存期:
error[E0106]: missing lifetime specifier
--> src/main.rs:13:16
|
11 | type Out = &String;
| ^ expected lifetime parameter
I cannot figure out a way to explicitly state the lifetime of the borrow, as it depends on the function itself. 我无法找出一种明确声明借用期限的方法,因为它取决于函数本身。
Taking inspiration from the Deref
trait , you can remove the reference from the associated type and instead just note in the trait that you want to return a reference to the associated type: 从
Deref
特征中获取灵感,您可以从关联的类型中删除引用,而只是在特征中注明要返回对关联类型的引用:
trait MutateOut {
type Out;
fn mut_out(&mut self) -> &Self::Out;
}
impl MutateOut for Test {
type Out = String;
fn mut_out(&mut self) -> &Self::Out {
self.val = String::from("something");
&self.val
}
}
Here it is in the playground . 这是在操场上 。 Given that your function name was
mut_out
, if a mutable reference is what you were after, here is a playground example with that as well . 假设您的函数名是
mut_out
,那么如果要使用可变引用,那么这里也是一个操场示例 。
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