[英]Python : class definition with **kwargs
When trying to instantiate the following class I am getting the following error : 尝试实例化以下类时,我收到以下错误:
"TypeError: __init__() takes exactly 2 arguments (3 given)"
Do you know what would be the issue ? 你知道这会是什么问题吗? Here is the class definition :
这是类定义:
class db_create_table():
'''
doc here
'''
def __init__(self,TableName, **kwargs ):
self.TableName = TableName
for k,v in kwargs.iteritems():
setattr(self, k, k)
schema = {"id" : { "type":"Integer", "primary":"primary_key=True", "unique":"unique = True"},
"col1" : { "type":"String()", "primary":"primary_key=False", "unique":"unique = True"},
"col2" : { "type":"String()", "primary":"primary_key=False", "unique":"unique = False"},
"col3" : { "type":"String()", "primary":"primary_key=False", "unique":"unique = False"},
"col4" : { "type":"String()", "primary":"primary_key=False", "unique":"unique = False"},
"CreatedOn" : { "type":"DateTime", "primary":"", "unique":"unique = False"},
"UpdatedOn" : { "type":"DateTime", "primary":"primary_key=False", "unique":"unique = False"},
}
db_create_table('Table1', schema)
In order to pass schema
and to unpack it into **kwargs
, you have to use **schema
: 为了传递
schema
并将其解压缩到**kwargs
,你必须使用**schema
:
db_create_table('Table1', **schema)
Explanation: The single asterisk form ( *args
) unpacks a sequence to form an argument list, while the double asterisk form ( **kwargs
) unpacks a dict-like object to a keyworded argument list. 说明:单个星号形式(
*args
)解包序列以形成参数列表,而双星号形式( **kwargs
)将类似dict的对象解压缩到keyworded参数列表。
Without any asterisk, the given object will directly passed as it is, without any unpacking. 没有任何星号,给定的对象将直接传递,而不进行任何解包。
See also how to use *args and **kwargs in Python . 另请参阅如何在Python中使用* args和** kwargs 。
The kwargs parameter in the function is capturing keyword arguments; 函数中的kwargs参数是捕获关键字参数; you are passing a single object without unpacking it.
您正在传递单个对象而不解压缩它。
You either need to pass it with **, so it gets unpacked, or add *args to the function definition. 您需要使用**传递它,因此它会被解压缩,或者将* args添加到函数定义中。 For example, look how the function interprets the arguments:
例如,查看函数如何解释参数:
def func(*args, **kwargs):
print args
print kwargs
func(arg)
func(*arg)
func(*arg, keyword='key')
output: 输出:
(('one', 'two'),) -- passed as arg, single element
{}
('one', 'two') -- passed as *arg - object is unpacked
{}
('one', 'two')
{'keyword': 'key'} -- keyword arg looks like that
As you pass positional args with *args, you can pass keyword args with **kwargs when calling the func. 当您使用* args传递位置参数时,您可以在调用func时传递带有** kwargs的关键字参数。
You're passing two args , but are only catching kwargs . 你传递了两个args ,但只是抓住了kwargs 。
schema
is being passed as a positional argument which would be caught by *args
; schema
作为位置参数传递,该参数将被*args
捕获; if you wanted it to be caught by **kwargs
you'd have to pass it as keyword argument: 如果你想让它被
**kwargs
捕获,你必须将它作为关键字参数传递:
db_create_table('Table1', schema=schema)
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